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anonymous
 one year ago
What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4?
anonymous
 one year ago
What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4?

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amilapsn
 one year ago
Best ResponseYou've already chosen the best response.0A function is said to be discontinuous at a point if we can't draw the graph without lifting our pen at that point.

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2in a function like this the discontinuity will occur where the denominator = 0 \[f(x) = \frac{ 5x ^{2}+5x12 }{ x+4 }\] If you set f(x) = 0 then you are left with just the quadratic to solve

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2CORRECTION  should be 2x^2 above BUT 2x^2+5x12 = (x+4)(2x3) so the equation becomes y=2x3 which has no discontinuity. Have I interpreted the equation correctly?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Isnt this still a discontinuous function?

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2if the equation is \[f(x) = \frac{ (2x)^{2}+5x12 }{ (x+4) }\] THEN my comments above are true because(2x)^2 = 4x^2 @sweetburger It looks like it should be  but because the denominator cancels with the factor in the numerator it becomes a continulas straight line

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Yea I realized when I graphed it that you are indeed correct.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Wait actually according to my graphing calculator there is a large gap in the graph

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0ill screenshot it one second

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2the question asks for the 'zero' but in most cases there are 2 zeroes I think I may have misinterpreted the way the question is written  or it is written incorrectly.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0welp i was doing 5x^2 instead of 2x^2 my bad

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2soz  that was my initial typo but there are 2 zeroes in other values for ax^2

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Yea, I see the 2 zeroe values with the correct equation. I understand where your answer came from now.

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2no  my point is that if the equation is as I wrote then there is ONE zero (as it is a straight line  but NO discontinuity If the equation is other, then there are 2 zeroes , and a discontinuity @ x=4

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I mean I see where your coming from as the x+4 cancel out and your left with a straight line with no discontinuities represented by y=2x+3. At least i think this is what your were saying.

MrNood
 one year ago
Best ResponseYou've already chosen the best response.2yes  that's it I still think there is an error with the question, or with my interpretation. But the asker is offline so I'll wait foe his reply.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Yea the question seems to be misworded in some way or the asker typed it in wrong.
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