anonymous
  • anonymous
Find the height, in feet, of the rock after 5 seconds in the air. A rock is launched from a cannon. It’s height, h(x), can be represented by a quadratic function in terms of time, x, in seconds. After 1 second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@JoKeR0331
anonymous
  • anonymous
someone please help
anonymous
  • anonymous
pleaseeeee

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More answers

anonymous
  • anonymous
@unknownunknown
unknownunknown
  • unknownunknown
Do we have the angle of the cannon, is it firing directly upward?
anonymous
  • anonymous
it dosent say @unknownunknown
unknownunknown
  • unknownunknown
Can you do a screenshot of the question?
anonymous
  • anonymous
i cant its a test
anonymous
  • anonymous
do you want me to put every detail? @unknownunknown
unknownunknown
  • unknownunknown
We will need every detail.. that's insufficient information as it is.
anonymous
  • anonymous
Help please A rock is launched from a cannon. It's height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.After one second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air. Find the height, in feet, of the rock after 5 seconds in the air.
anonymous
  • anonymous
@unknownunknown all of it
unknownunknown
  • unknownunknown
Alright well, I'm going to assume a lot, so I can't see if this will be definitely correct, but the question contains incorrect information to answer properly. So we'll just have to proceed with what we have.. Let me confirm the equation to make sure, one sec.
unknownunknown
  • unknownunknown
insufficient information*
anonymous
  • anonymous
so you cant solve it at all? @unknownunknown
anonymous
  • anonymous
@unknownunknown ?????
unknownunknown
  • unknownunknown
Is there a multiple choice or you must write the answer?
anonymous
  • anonymous
must write the answer @unknownunknown
unknownunknown
  • unknownunknown
So, if we let y equal the displacement, y = 9.8*t^2/2 + initial velocity * time So first of all, we'll need to solve for the initial velocity, can you rearrange the equation to solve for v? y=9.8*t^2/2 + v * t
unknownunknown
  • unknownunknown
Actually since it's coming down, we should make 9.8*t^2/2 negative. So y = -9.8*t^2/2 + v*t
anonymous
  • anonymous
i think its a large number for feet @unknownunknown
unknownunknown
  • unknownunknown
I'd say the answer is approximately 527, somewhere around there.
anonymous
  • anonymous
its not @unknownunknown
unknownunknown
  • unknownunknown
And how do you know that?
anonymous
  • anonymous
i just tried
anonymous
  • anonymous
@unknownunknown
unknownunknown
  • unknownunknown
Ok wait, let me work it out
unknownunknown
  • unknownunknown
Have you covered gravity in class? g = 9.8?
anonymous
  • anonymous
no @unknownunknown
unknownunknown
  • unknownunknown
Okay so. Let's say we have a function.. f(t) = -11*t^2 + 140*t If we plug into this equation t=1, we have -11 + 140 = 129 which satisfies the first part Then if we plug t=2, we have -11*4 + 140*2 = 236 which satisfies the second part
unknownunknown
  • unknownunknown
So then for f(5) = -11*25 + 140*5 = 425
anonymous
  • anonymous
right @unknownunknown
unknownunknown
  • unknownunknown
Okay, good.
anonymous
  • anonymous
can you help with another one @unknownunknown
anonymous
  • anonymous
Widget wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $23 to produce 2 widgets, $103 to produce 4 widgets, and $631 to produce 6 widgets.
anonymous
  • anonymous
@unknownunknown

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