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anonymous
 one year ago
Find the height, in feet, of the rock after 5 seconds in the air.
A rock is launched from a cannon. It’s height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.
After 1 second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air.
anonymous
 one year ago
Find the height, in feet, of the rock after 5 seconds in the air. A rock is launched from a cannon. It’s height, h(x), can be represented by a quadratic function in terms of time, x, in seconds. After 1 second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air.

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unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Do we have the angle of the cannon, is it firing directly upward?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it dosent say @unknownunknown

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Can you do a screenshot of the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to put every detail? @unknownunknown

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0We will need every detail.. that's insufficient information as it is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Help please A rock is launched from a cannon. It's height, h(x), can be represented by a quadratic function in terms of time, x, in seconds.After one second, the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air. Find the height, in feet, of the rock after 5 seconds in the air.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@unknownunknown all of it

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Alright well, I'm going to assume a lot, so I can't see if this will be definitely correct, but the question contains incorrect information to answer properly. So we'll just have to proceed with what we have.. Let me confirm the equation to make sure, one sec.

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0insufficient information*

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you cant solve it at all? @unknownunknown

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@unknownunknown ?????

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Is there a multiple choice or you must write the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0must write the answer @unknownunknown

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0So, if we let y equal the displacement, y = 9.8*t^2/2 + initial velocity * time So first of all, we'll need to solve for the initial velocity, can you rearrange the equation to solve for v? y=9.8*t^2/2 + v * t

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Actually since it's coming down, we should make 9.8*t^2/2 negative. So y = 9.8*t^2/2 + v*t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think its a large number for feet @unknownunknown

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0I'd say the answer is approximately 527, somewhere around there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its not @unknownunknown

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0And how do you know that?

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Ok wait, let me work it out

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Have you covered gravity in class? g = 9.8?

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0Okay so. Let's say we have a function.. f(t) = 11*t^2 + 140*t If we plug into this equation t=1, we have 11 + 140 = 129 which satisfies the first part Then if we plug t=2, we have 11*4 + 140*2 = 236 which satisfies the second part

unknownunknown
 one year ago
Best ResponseYou've already chosen the best response.0So then for f(5) = 11*25 + 140*5 = 425

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right @unknownunknown

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help with another one @unknownunknown

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Widget wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $23 to produce 2 widgets, $103 to produce 4 widgets, and $631 to produce 6 widgets.
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