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hi ...
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please explain how the first equation becomes the second equation
plug 3x^2/4 into h^2
so you will get x^2/4 + 3x^2/4
=x^2
thats how 2nd equation becomes first equation... on how first becomes the second, subtract x^2/4 on both sides to isolate h^2
yeh
i hate typing now
\(x^2/4 + h^2 =x^2 \\ x^2/4 - x^2/4 + h^2 = x^2 - x^2/4 \\ h^2 = x^2 (1-1/4) = .. \) got these steps?
um
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this is the actual question.
i just don't understand the part where \[\frac{ x^2 }{ 4 } +h^2 =x^2 \rightarrow h^2 = \frac{ 3x^2 }{ 4 }\]
sry
yeah, x^2/4 is moved to other side of = by subtracting it from both sides
\(x^2/4 + h^2 =x^2 \\ x^2/4 - x^2/4 + h^2 = x^2 - x^2/4 \\ h^2 = x^2 (1-1/4) =x^2 (3/4) = 3x^2/4 \)
oh i think i get it now.
\[x^2\]
how does this turn into a fraction?
x^2 - x^2/4 now we see "x^2" in both the terms so we factor it out. x^2 (1-1/4) that makes it x^2 * (3/4) or 3x^2/4
|dw:1433166388320:dw|
correct?
yep, you got it :)
yay u did ur magic again hartnn, thank you :)
welcome ^_^

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