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Mindblast3r

  • one year ago

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  1. anonymous
    • one year ago
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    hi ...

  2. anonymous
    • one year ago
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    ?????

  3. mindblast3r
    • one year ago
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  4. mindblast3r
    • one year ago
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    please explain how the first equation becomes the second equation

  5. anonymous
    • one year ago
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    plug 3x^2/4 into h^2

  6. anonymous
    • one year ago
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    so you will get x^2/4 + 3x^2/4

  7. anonymous
    • one year ago
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    =x^2

  8. hartnn
    • one year ago
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    thats how 2nd equation becomes first equation... on how first becomes the second, subtract x^2/4 on both sides to isolate h^2

  9. anonymous
    • one year ago
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    yeh

  10. anonymous
    • one year ago
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    i hate typing now

  11. hartnn
    • one year ago
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    \(x^2/4 + h^2 =x^2 \\ x^2/4 - x^2/4 + h^2 = x^2 - x^2/4 \\ h^2 = x^2 (1-1/4) = .. \) got these steps?

  12. mindblast3r
    • one year ago
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    um

  13. mindblast3r
    • one year ago
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  14. mindblast3r
    • one year ago
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    this is the actual question.

  15. mindblast3r
    • one year ago
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    i just don't understand the part where \[\frac{ x^2 }{ 4 } +h^2 =x^2 \rightarrow h^2 = \frac{ 3x^2 }{ 4 }\]

  16. mindblast3r
    • one year ago
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    sry

  17. hartnn
    • one year ago
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    yeah, x^2/4 is moved to other side of = by subtracting it from both sides

  18. hartnn
    • one year ago
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    \(x^2/4 + h^2 =x^2 \\ x^2/4 - x^2/4 + h^2 = x^2 - x^2/4 \\ h^2 = x^2 (1-1/4) =x^2 (3/4) = 3x^2/4 \)

  19. mindblast3r
    • one year ago
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    oh i think i get it now.

  20. mindblast3r
    • one year ago
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    \[x^2\]

  21. mindblast3r
    • one year ago
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    how does this turn into a fraction?

  22. hartnn
    • one year ago
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    x^2 - x^2/4 now we see "x^2" in both the terms so we factor it out. x^2 (1-1/4) that makes it x^2 * (3/4) or 3x^2/4

  23. mindblast3r
    • one year ago
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    |dw:1433166388320:dw|

  24. mindblast3r
    • one year ago
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    correct?

  25. hartnn
    • one year ago
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    yep, you got it :)

  26. mindblast3r
    • one year ago
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    yay u did ur magic again hartnn, thank you :)

  27. hartnn
    • one year ago
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    welcome ^_^

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