BloomLocke367
  • BloomLocke367
Simplify the trig expression.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
BloomLocke367
  • BloomLocke367
\(\Large\frac{sin^2\theta}{1-\cos\theta}\)
amilapsn
  • amilapsn
\(\color{blueviolet}{\Huge\sf{sin^2\theta+cos^2 \theta\equiv 1}}\)
amilapsn
  • amilapsn
k?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

BloomLocke367
  • BloomLocke367
yes. but that's not an option.
amilapsn
  • amilapsn
You are not allowed to use that ?
BloomLocke367
  • BloomLocke367
I'm confused. how do I use that?
BloomLocke367
  • BloomLocke367
http://prntscr.com/7bv1ju my choices
amilapsn
  • amilapsn
instead of \(\sin^2\theta\) what would you substitute?
BloomLocke367
  • BloomLocke367
1-cos^2? @amilapsn
amilapsn
  • amilapsn
\color{blueviolet}{\Huge\sf{Yes.}}
BloomLocke367
  • BloomLocke367
you forgot the `\(` and `\)`
BloomLocke367
  • BloomLocke367
then what do I do?
amilapsn
  • amilapsn
I did it intentionally... :D
BloomLocke367
  • BloomLocke367
okay XD
amilapsn
  • amilapsn
then use...
BloomLocke367
  • BloomLocke367
what's a and b?
amilapsn
  • amilapsn
\[\color{blueviolet}{\Huge\sf{a^2-b^2\equiv(a-b)(a+b)}}\]
amilapsn
  • amilapsn
just have a guess...
amilapsn
  • amilapsn
(I just asked you to factorize 1-cos^\theta)
BloomLocke367
  • BloomLocke367
right now I have 1-cos^2/1-cos (theta)
BloomLocke367
  • BloomLocke367
@amilapsn Can you still help? I'm confused
BloomLocke367
  • BloomLocke367
@amistre64
amilapsn
  • amilapsn
can you factorize \(1-\cos^2\theta\)?
BloomLocke367
  • BloomLocke367
how?
BloomLocke367
  • BloomLocke367
@amilapsn
amilapsn
  • amilapsn
you know this?
amilapsn
  • amilapsn
\color{blueviolet}{\Huge\sf{a^2-b^2=(a-b)(a+b)}}
BloomLocke367
  • BloomLocke367
not really
amilapsn
  • amilapsn
if you simplify the r.h.s. you'll get l.h.s. and you can prove it yourself....
BloomLocke367
  • BloomLocke367
rhs? lhs? what's that?
Nnesha
  • Nnesha
rhs = right hand side lhs = left hand side
BloomLocke367
  • BloomLocke367
I still don't know how to do it
amilapsn
  • amilapsn
\[\color{blueviolet}{\Huge\sf{1-\cos^2\theta=(1-\cos\theta)(1+\cos\theta)}}\]
amilapsn
  • amilapsn
ok?
BloomLocke367
  • BloomLocke367
yes?
amilapsn
  • amilapsn
Now you have the answer
BloomLocke367
  • BloomLocke367
oh, so is the answer 1+cos theta?
amilapsn
  • amilapsn
yepp
BloomLocke367
  • BloomLocke367
\(\Huge\color{lime}{Thank~you!}\)
amilapsn
  • amilapsn
\[\color{blue}{\Huge\sf{You're ~Welcome!}}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.