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BloomLocke367

  • one year ago

Simplify the trig expression.

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  1. BloomLocke367
    • one year ago
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    \(\Large\frac{sin^2\theta}{1-\cos\theta}\)

  2. amilapsn
    • one year ago
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    \(\color{blueviolet}{\Huge\sf{sin^2\theta+cos^2 \theta\equiv 1}}\)

  3. amilapsn
    • one year ago
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    k?

  4. BloomLocke367
    • one year ago
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    yes. but that's not an option.

  5. amilapsn
    • one year ago
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    You are not allowed to use that ?

  6. BloomLocke367
    • one year ago
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    I'm confused. how do I use that?

  7. BloomLocke367
    • one year ago
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    http://prntscr.com/7bv1ju my choices

  8. amilapsn
    • one year ago
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    instead of \(\sin^2\theta\) what would you substitute?

  9. BloomLocke367
    • one year ago
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    1-cos^2? @amilapsn

  10. amilapsn
    • one year ago
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    \color{blueviolet}{\Huge\sf{Yes.}}

  11. BloomLocke367
    • one year ago
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    you forgot the `\(` and `\)`

  12. BloomLocke367
    • one year ago
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    then what do I do?

  13. amilapsn
    • one year ago
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    I did it intentionally... :D

  14. BloomLocke367
    • one year ago
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    okay XD

  15. amilapsn
    • one year ago
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    then use...

  16. BloomLocke367
    • one year ago
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    what's a and b?

  17. amilapsn
    • one year ago
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    \[\color{blueviolet}{\Huge\sf{a^2-b^2\equiv(a-b)(a+b)}}\]

  18. amilapsn
    • one year ago
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    just have a guess...

  19. amilapsn
    • one year ago
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    (I just asked you to factorize 1-cos^\theta)

  20. BloomLocke367
    • one year ago
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    right now I have 1-cos^2/1-cos (theta)

  21. BloomLocke367
    • one year ago
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    @amilapsn Can you still help? I'm confused

  22. BloomLocke367
    • one year ago
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    @amistre64

  23. amilapsn
    • one year ago
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    can you factorize \(1-\cos^2\theta\)?

  24. BloomLocke367
    • one year ago
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    how?

  25. BloomLocke367
    • one year ago
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    @amilapsn

  26. amilapsn
    • one year ago
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    you know this?

  27. amilapsn
    • one year ago
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    \color{blueviolet}{\Huge\sf{a^2-b^2=(a-b)(a+b)}}

  28. BloomLocke367
    • one year ago
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    not really

  29. amilapsn
    • one year ago
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    if you simplify the r.h.s. you'll get l.h.s. and you can prove it yourself....

  30. BloomLocke367
    • one year ago
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    rhs? lhs? what's that?

  31. Nnesha
    • one year ago
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    rhs = right hand side lhs = left hand side

  32. BloomLocke367
    • one year ago
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    I still don't know how to do it

  33. amilapsn
    • one year ago
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    \[\color{blueviolet}{\Huge\sf{1-\cos^2\theta=(1-\cos\theta)(1+\cos\theta)}}\]

  34. amilapsn
    • one year ago
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    ok?

  35. BloomLocke367
    • one year ago
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    yes?

  36. amilapsn
    • one year ago
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    Now you have the answer

  37. BloomLocke367
    • one year ago
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    oh, so is the answer 1+cos theta?

  38. amilapsn
    • one year ago
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    yepp

  39. BloomLocke367
    • one year ago
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    \(\Huge\color{lime}{Thank~you!}\)

  40. amilapsn
    • one year ago
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    \[\color{blue}{\Huge\sf{You're ~Welcome!}}\]

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