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anonymous

  • one year ago

Solve by using the perfect squares method. x2 + 16x + 64= 0

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  1. anonymous
    • one year ago
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    @mathmate

  2. pooja195
    • one year ago
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  3. pooja195
    • one year ago
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    \[\huge x^2 + \sqrt{16x}+ \sqrt{64}= 0\]

  4. anonymous
    • one year ago
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    what is that

  5. pooja195
    • one year ago
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    we square root the perfect squares

  6. mathmate
    • one year ago
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    @pooja195 We squareroot the first and last terms. \(\sqrt{x^2}=x\) and \(\sqrt{64}=8\)

  7. mathmate
    • one year ago
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    So far so good, the first and last terms are perfect squares. Next:

  8. mathmate
    • one year ago
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    we double the product, 2(8x)=16x If this equals the absolute value of the middle term |16x|, we have a perfect square expression. The sign between x and 8 is determined by the sign of the middle term.

  9. mathmate
    • one year ago
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    So \(x^2 + 16x + 64= (x+8)^2\), or \((x+8)^2=0\)

  10. mathmate
    • one year ago
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    @Nitaoffaith I'll let you take it from here to finish solving the equation.

  11. anonymous
    • one year ago
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    ok thx

  12. mathmate
    • one year ago
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    You're welcome! :)

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