anonymous
  • anonymous
Solve by using the perfect squares method. x2 + 16x + 64= 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@mathmate
pooja195
  • pooja195
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pooja195
  • pooja195
\[\huge x^2 + \sqrt{16x}+ \sqrt{64}= 0\]

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anonymous
  • anonymous
what is that
pooja195
  • pooja195
we square root the perfect squares
mathmate
  • mathmate
@pooja195 We squareroot the first and last terms. \(\sqrt{x^2}=x\) and \(\sqrt{64}=8\)
mathmate
  • mathmate
So far so good, the first and last terms are perfect squares. Next:
mathmate
  • mathmate
we double the product, 2(8x)=16x If this equals the absolute value of the middle term |16x|, we have a perfect square expression. The sign between x and 8 is determined by the sign of the middle term.
mathmate
  • mathmate
So \(x^2 + 16x + 64= (x+8)^2\), or \((x+8)^2=0\)
mathmate
  • mathmate
@Nitaoffaith I'll let you take it from here to finish solving the equation.
anonymous
  • anonymous
ok thx
mathmate
  • mathmate
You're welcome! :)

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