## anonymous one year ago Solve by using the perfect squares method. x2 + 16x + 64= 0

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1. anonymous

@mathmate

2. pooja195

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3. pooja195

$\huge x^2 + \sqrt{16x}+ \sqrt{64}= 0$

4. anonymous

what is that

5. pooja195

we square root the perfect squares

6. mathmate

@pooja195 We squareroot the first and last terms. $$\sqrt{x^2}=x$$ and $$\sqrt{64}=8$$

7. mathmate

So far so good, the first and last terms are perfect squares. Next:

8. mathmate

we double the product, 2(8x)=16x If this equals the absolute value of the middle term |16x|, we have a perfect square expression. The sign between x and 8 is determined by the sign of the middle term.

9. mathmate

So $$x^2 + 16x + 64= (x+8)^2$$, or $$(x+8)^2=0$$

10. mathmate

@Nitaoffaith I'll let you take it from here to finish solving the equation.

11. anonymous

ok thx

12. mathmate

You're welcome! :)