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anonymous
 one year ago
What is the fourth term in this multiplication pattern?
multiplication pattern using the formula 2 • 6n – 1
A.
12
B.
72
C.
432
D.
2592
anonymous
 one year ago
What is the fourth term in this multiplication pattern? multiplication pattern using the formula 2 • 6n – 1 A. 12 B. 72 C. 432 D. 2592

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you asking what n is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if so what does this equal?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0shoot n is a exponent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok.. so please rewrite the Question. Im not sure what the question is. Are we solving for N? or what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks like it is: \[2\times 6^n 1\] amd we meed to find the fourth term

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then sorry i cant help here/ I dont understand that. Sorreh @baconbaby1334

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or is it \[2\times 6^{(n1)}\]???? beacause the answers dont match for the other form...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay I think it is that but I dont understand how that works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the fourth term we just need to replace n by 4 we get: \[2\times6^{(41)}=2\times6^{3}\] can you calculate that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0great! so it is answer C !
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