anonymous
  • anonymous
What is the fourth term in this multiplication pattern? multiplication pattern using the formula 2 • 6n – 1 A. 12 B. 72 C. 432 D. 2592
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
are you asking what n is?
anonymous
  • anonymous
if so what does this equal?
anonymous
  • anonymous
shoot n is a exponent

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anonymous
  • anonymous
Im so stupid
anonymous
  • anonymous
ok.. so please rewrite the Question. Im not sure what the question is. Are we solving for N? or what?
anonymous
  • anonymous
looks like it is: \[2\times 6^n -1\] amd we meed to find the fourth term
anonymous
  • anonymous
yay that
anonymous
  • anonymous
Then sorry i cant help here/ I dont understand that. Sorreh @baconbaby1334
anonymous
  • anonymous
or is it \[2\times 6^{(n-1)}\]???? beacause the answers dont match for the other form...
anonymous
  • anonymous
yay I think it is that but I dont understand how that works
anonymous
  • anonymous
for the fourth term we just need to replace n by 4 we get: \[2\times6^{(4-1)}=2\times6^{3}\] can you calculate that?
anonymous
  • anonymous
432
anonymous
  • anonymous
great! so it is answer C !
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
yw!

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