http://prntscr.com/7bvs3w @Nnesha

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draw a triangle and find 3rd side
what do you mean? (sorry, I really don't understand trig)
|dw:1433170800461:dw| given order pair (x,y) x represent cosine y represent sin and \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

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how do I find csc and sec?
first you have to find 3rd side of right triangle |dw:1433171058392:dw| sin = opposite /hyp and cos = adjacent /hyp
now apply Pythagorean theorem to find 3rd side
13
yep right |dw:1433171191619:dw| now what is reciprocal of sec and csc ?? for example tan = sin/cos sec= ?
I don't know
mhm that's important part of trig you have to know this \[\huge\rm sec = \frac{ 1 }{ \cos } , \csc =\frac{ 1 }{ \sin } ,\cot =\frac{ \cos }{ \sin } \]
cos is adjacent over hyp so 1/adjacent/hpy = ? what is adjacent of right triangle
12
so 1/12/13?
yep right now multiply top wit the reciprocal of the bottom
hang on, I have to volunteer now, I'll be back in 2 hours, approximately.
aright :-)
@Nnesha I'm back.. I know it took forever, but I never got the chance after I finished working
I got 1? is that right? @Nnesha
nope how did you get 1?
\(\color{blue}{\text{Originally Posted by}}\) @BloomLocke367 so 1/12/13? \(\color{blue}{\text{End of Quote}}\) multiply top wit the reciprocal of the bottom fraction
ohh I didn't use the reciprocal
I got 169/144
mhm how did you get 169 and 133 don't square them |dw:1433196171493:dw|
what?
5,12 aand 13 are sides of right triangle what is cos = ? sin = ?
\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
cos is 12/13 and sin is 5/13
yes right now you need sec and csc so sec= 1/cos which is \[\frac{ 1 }{ \frac{12}{13}}\]
multiply 1 by the reciprocal of the bottom fraction
for example \[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } = \frac{ a }{ b } \times \frac{ d }{ c }\]
so 13/12
yeah!
csc = ?
and that's sec? that's not an option...
i did it wrong |dw:1433196991226:dw| sin is opposite so (cosine , sin) x coordinate would be adjacent which suppose to be 5
so cos = 5/13 sin = 12/13
so csc = what ? and sec = ?
sec=13/5 and csc=13/12
Thank you so much!
np :-)
Can you help more?
mhm maybe...

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