In a small company of 10 people the salaries are as follows: 5 people earn $25,000, 3 earn $27,000, 1 earns $34,000, and the owner earns $60,000 What is the mean and standard deviation (to the nearest dollar) of their salaries? Mean salary:_______________ $a0 Standard Deviation: ______________$a1

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In a small company of 10 people the salaries are as follows: 5 people earn $25,000, 3 earn $27,000, 1 earns $34,000, and the owner earns $60,000 What is the mean and standard deviation (to the nearest dollar) of their salaries? Mean salary:_______________ $a0 Standard Deviation: ______________$a1

Mathematics
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Well for the mean you need to add count divide. Add 25,000 (5 times), 27,000 (3 times), 34,000, and 60,000. Count the number of people (10), and then divide the sum by that number.
what should i get
Well, what did you get?

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Other answers:

hold up
im confused lol
Lol ok focus on the adding first. You should be adding 10 numbers. 25000+25000+25000+25000+25000+27000+27000+27000+34000+60000
300000
???????
Yep :) Then you need to divide by the number of people
divide it by 10
Yes
30000
the mean salary is 300000 and the standard deviation is 30000
???
Not quite. The 30,000 that you got is the mean.
well then now what
https://www.mathsisfun.com/data/standard-deviation-formulas.html Now you have to subtract the mean from each number and square the result.
??????????
The first number (going back to the original problem) is 25,000. Subtract 30,000, and then take that difference and square it (multiply it by itself).

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