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anonymous

  • one year ago

In a small company of 10 people the salaries are as follows: 5 people earn $25,000, 3 earn $27,000, 1 earns $34,000, and the owner earns $60,000 What is the mean and standard deviation (to the nearest dollar) of their salaries? Mean salary:_______________ $a0 Standard Deviation: ______________$a1

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  1. kobeni-chan
    • one year ago
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    Well for the mean you need to add count divide. Add 25,000 (5 times), 27,000 (3 times), 34,000, and 60,000. Count the number of people (10), and then divide the sum by that number.

  2. anonymous
    • one year ago
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    what should i get

  3. kobeni-chan
    • one year ago
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    Well, what did you get?

  4. anonymous
    • one year ago
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    hold up

  5. anonymous
    • one year ago
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    im confused lol

  6. kobeni-chan
    • one year ago
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    Lol ok focus on the adding first. You should be adding 10 numbers. 25000+25000+25000+25000+25000+27000+27000+27000+34000+60000

  7. anonymous
    • one year ago
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    300000

  8. anonymous
    • one year ago
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    ???????

  9. kobeni-chan
    • one year ago
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    Yep :) Then you need to divide by the number of people

  10. anonymous
    • one year ago
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    divide it by 10

  11. kobeni-chan
    • one year ago
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    Yes

  12. anonymous
    • one year ago
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    30000

  13. anonymous
    • one year ago
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    the mean salary is 300000 and the standard deviation is 30000

  14. anonymous
    • one year ago
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    ???

  15. kobeni-chan
    • one year ago
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    Not quite. The 30,000 that you got is the mean.

  16. anonymous
    • one year ago
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    well then now what

  17. kobeni-chan
    • one year ago
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    https://www.mathsisfun.com/data/standard-deviation-formulas.html Now you have to subtract the mean from each number and square the result.

  18. anonymous
    • one year ago
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    ??????????

  19. kobeni-chan
    • one year ago
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    The first number (going back to the original problem) is 25,000. Subtract 30,000, and then take that difference and square it (multiply it by itself).

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