Find the solutions of the system. Y=x^2+3x-4 y=2x+2 a. (-3,6) and (2,-4) b. (-3,-4) and (2,6) c. (-3,4) and (-2,-2) d. no solution

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Find the solutions of the system. Y=x^2+3x-4 y=2x+2 a. (-3,6) and (2,-4) b. (-3,-4) and (2,6) c. (-3,4) and (-2,-2) d. no solution

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I know that there is a way to solve this using the equations, but it's been years (at least 5) since I was last in an algebra class. So how I would solve this would be to make the two lines on a graph, and the answer is where the two lines meet on the graph.
another way to solve is to set the y values equal and solve the one equation with one variable . Use this value in either of the original expressions to get the value of y
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