anonymous
  • anonymous
A right triangle has base (x - 7) units and height (2x - 10) units. Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points) Part B: What is the area of the triangle? (3 points) Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@ganeshie8 @Nnesha @hartnn
anonymous
  • anonymous
Please help Anyone
anonymous
  • anonymous
@mathmate @welshfella Can you guys help? I have a general idea of what I need to do for part one, but I get really lost afterwards.

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More answers

welshfella
  • welshfella
square of hypotenuse , by Pythagoras theorem = sum of squares on the other 2 sides = (x - 7^2 + (2x - 10)^2
anonymous
  • anonymous
I got that much, but I need to simplify it I believe
anonymous
  • anonymous
@welshfella
kobeni-chan
  • kobeni-chan
What do you have that you need to simplify?
anonymous
  • anonymous
I need the square length of the hypotenuse. so wouldn't I need to simplify (x-7)^2 + (2x+10)= C^2?
anonymous
  • anonymous
Like I know that much but I don't know what to do afterwards. do I square everything?
kobeni-chan
  • kobeni-chan
You need to square (x-7) and (2x-10) right now. If you have a scientific calculator you can do this easily, but if you have a reg. calculator then do (x-7)(x-7) and use the distributive property. Then do the same with (2x-10)(2x-10)
anonymous
  • anonymous
|dw:1433177251700:dw|
anonymous
  • anonymous
|dw:1433177275411:dw|
anonymous
  • anonymous
|dw:1433177299845:dw|
anonymous
  • anonymous
|dw:1433177325031:dw| ?
anonymous
  • anonymous
Did I do that part correct?
kobeni-chan
  • kobeni-chan
h/o
anonymous
  • anonymous
Oki cx
kobeni-chan
  • kobeni-chan
Yes that's right :) sorry if I'm slow to respond I'm doing my exam
anonymous
  • anonymous
Okay, so now I do (2x-10)(2x-10)?
kobeni-chan
  • kobeni-chan
Yep
anonymous
  • anonymous
|dw:1433177671889:dw| Sorry for the bad writing ;-;~
welshfella
  • welshfella
now had these 2 expansions together x&3 - 14x + 49 + 4x^2 - 40x + 100
welshfella
  • welshfella
**correction first term is x^2
anonymous
  • anonymous
add them?
welshfella
  • welshfella
yes
anonymous
  • anonymous
|dw:1433178085721:dw|
welshfella
  • welshfella
add like terms eg x^2 + 4x^2 = 5 x^2
welshfella
  • welshfella
yep
anonymous
  • anonymous
is that the answer? for part A I mean
welshfella
  • welshfella
yes
welshfella
  • welshfella
Part B the area = 1/2 * base * height = 1/2 * (x - 7) (2x - 10)
anonymous
  • anonymous
how do I do that o.O
anonymous
  • anonymous
@kobeni-chan ? ;-;~
welshfella
  • welshfella
to make it easier 1/2 * (2x - 10) = (x - 5) now work out (x - 7)(x - 5) and you gave the required area
welshfella
  • welshfella
* have
anonymous
  • anonymous
|dw:1433179051398:dw|
anonymous
  • anonymous
@amistre64 @Here_to_Help15
anonymous
  • anonymous
@mathstudent55 @paki @Luigi0210
anonymous
  • anonymous
@welshfella can you please help me
kobeni-chan
  • kobeni-chan
I'm so sorry I got very busy and forgot about your question :( what part are you on?
anonymous
  • anonymous
Part B I believe >.>
anonymous
  • anonymous
@Aureyliant >.>
anonymous
  • anonymous
Ok so Pt. B is asking the area.. what is your understanding of this Q?
anonymous
  • anonymous
That for the area, you need to do a=1/2*b*h since we already have b and h, we just plug it in. Right?
anonymous
  • anonymous
Yup!
anonymous
  • anonymous
I got that much, but when it comes to trying to find said area, I get completely lost
anonymous
  • anonymous
\[1/2*(2x-10)(x-7)\] is your equation
anonymous
  • anonymous
I know that much, but I don't know how to apply the 1/2 to the (x-7)
welshfella
  • welshfella
you've worked it out correctly alice
anonymous
  • anonymous
so is that trinomial the Area?
anonymous
  • anonymous
You can either take it's inverse out, but since it's an expression & not an equation, it's like dividing (x-7) by 2.
welshfella
  • welshfella
apply the half to (2x -10) first makes it easier 1/2 * (2x - 10 ) = x - 5
anonymous
  • anonymous
^ Agreed
welshfella
  • welshfella
so it comes down to (x -5)(x - 7) which you worked out correctly in an earlier post alice
anonymous
  • anonymous
I did (x-5)(x-7). Is there no other step afterwards?
anonymous
  • anonymous
Nope. You can check your work by multiplying again, and you should be getting the same answer you started with.

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