At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Please help
Anyone

I got that much, but I need to simplify it I believe

What do you have that you need to simplify?

I need the square length of the hypotenuse. so wouldn't I need to simplify (x-7)^2 + (2x+10)= C^2?

Like I know that much but I don't know what to do afterwards. do I square everything?

|dw:1433177251700:dw|

|dw:1433177275411:dw|

|dw:1433177299845:dw|

|dw:1433177325031:dw| ?

Did I do that part correct?

h/o

Oki cx

Yes that's right :) sorry if I'm slow to respond I'm doing my exam

Okay, so now I do (2x-10)(2x-10)?

Yep

|dw:1433177671889:dw|
Sorry for the bad writing ;-;~

now had these 2 expansions together
x&3 - 14x + 49 + 4x^2 - 40x + 100

**correction first term is x^2

add them?

yes

|dw:1433178085721:dw|

add like terms
eg x^2 + 4x^2 = 5 x^2

yep

is that the answer? for part A I mean

yes

Part B
the area = 1/2 * base * height
= 1/2 * (x - 7) (2x - 10)

how do I do that o.O

* have

|dw:1433179051398:dw|

@welshfella can you please help me

I'm so sorry I got very busy and forgot about your question :( what part are you on?

Part B
I believe >.>

@Aureyliant >.>

Ok so Pt. B is asking the area.. what is your understanding of this Q?

Yup!

I got that much, but when it comes to trying to find said area, I get completely lost

\[1/2*(2x-10)(x-7)\] is your equation

I know that much, but I don't know how to apply the 1/2 to the (x-7)

you've worked it out correctly alice

so is that trinomial the Area?

apply the half to (2x -10) first makes it easier
1/2 * (2x - 10 ) = x - 5

^ Agreed

so it comes down to
(x -5)(x - 7) which you worked out correctly in an earlier post alice

I did (x-5)(x-7). Is there no other step afterwards?