Given cos(theta)=4/9 and csc(theta)<0, find sin(theta) and tan(theta).

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Given cos(theta)=4/9 and csc(theta)<0, find sin(theta) and tan(theta).

Mathematics
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can you help me and i will help you too
@heatherchaloupek2004 What do you need help with hon?
cos(theta)=4/9, then \[\cos ^{2}(\theta)=16/81\] \[\sin(\theta)=\sqrt{1-\cos^{2}(\theta)}\] \[\sin(\theta)=\sqrt{1-16/81}=\sqrt{65}/9\] \[\tan(\theta)=\sin(\theta)/\cos(\theta)=\sqrt{65}/4\]

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@SwapnilP so, how do you get to sqrt(65)/9?
Here it is: \[We have \cos(\theta)=4/9 and \sin(\theta)=\sqrt{65}/9\] so \[\tan(\theta)=\sin(\theta)/\cos(\theta)=\[(\sqrt{65}/9)/(4/9)=(\sqrt{65}/9)*(9/4)=\sqrt{65}/4\]
\[\sqrt{1-16/81}=\sqrt{(81-16)/81}=\sqrt{65/81}=\sqrt{65}/\sqrt{81}=\sqrt{65}/9\]
LOh I gent it'!

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