A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Given cos(theta)=4/9 and csc(theta)<0, find sin(theta) and tan(theta).
anonymous
 one year ago
Given cos(theta)=4/9 and csc(theta)<0, find sin(theta) and tan(theta).

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me and i will help you too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@heatherchaloupek2004 What do you need help with hon?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos(theta)=4/9, then \[\cos ^{2}(\theta)=16/81\] \[\sin(\theta)=\sqrt{1\cos^{2}(\theta)}\] \[\sin(\theta)=\sqrt{116/81}=\sqrt{65}/9\] \[\tan(\theta)=\sin(\theta)/\cos(\theta)=\sqrt{65}/4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@SwapnilP so, how do you get to sqrt(65)/9?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here it is: \[We have \cos(\theta)=4/9 and \sin(\theta)=\sqrt{65}/9\] so \[\tan(\theta)=\sin(\theta)/\cos(\theta)=\[(\sqrt{65}/9)/(4/9)=(\sqrt{65}/9)*(9/4)=\sqrt{65}/4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{116/81}=\sqrt{(8116)/81}=\sqrt{65/81}=\sqrt{65}/\sqrt{81}=\sqrt{65}/9\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.