chaotic_butterflies
  • chaotic_butterflies
Geometric Series problem - Drake received 80 points on a project for school. He can make changes and receive one-tenth of the missing points back. He can do this 10 times. Create the formula for the sum of this geometric series, and explain your steps in solving for the maximum grade Drake can receive.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
chaotic_butterflies
  • chaotic_butterflies
@amistre64 if you're not busy could you possibly help me?
amistre64
  • amistre64
show me your idea ... and lets see if we can correct it
amistre64
  • amistre64
we may need to clarify this part: "He can make changes and receive one-tenth of the missing points back." what does it mean to you?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

chaotic_butterflies
  • chaotic_butterflies
Does it mean that he can receive 1/10th of the 20 questions that he missed?
chaotic_butterflies
  • chaotic_butterflies
Pardon my slow reply, my laptop keeps freezing >~<
amistre64
  • amistre64
it may mean, the 1/10 of the remaining points, after a submission.
chaotic_butterflies
  • chaotic_butterflies
So wait, you mean like he'll be tested on the 20 that he missed and if he got them all right, then he would only receive a potion of that score to be added to his original score? If that makes sense...
amistre64
  • amistre64
sounds like that to me. but its pretty vague still say he gets all of them correct in the submission, he gets an extra credit of 20(.1) = 2 but then what about any subsequent submission seeing how he got them all correct on the second try?
amistre64
  • amistre64
the grading scheme is rather senseless to me. he can obtain more extra credit by getting things wrong and resubmitting? it doesnt seem to be a well thought out question to me.
amistre64
  • amistre64
Drake received 80 points on a project for school. He can make changes and receive one-tenth of the missing points back. make changes? say 1+1 = 3 and receive 1/10 of the missing points back? How is this grading?
chaotic_butterflies
  • chaotic_butterflies
That's the thing about virtual school, they focus so much on silly scenarios for their questions, and not enough time explaining the content in the lessons! I've tried to get help from the sources that have been offered to me, but it just doesn't seem to connect
chaotic_butterflies
  • chaotic_butterflies
Oh hold on a minute I might have an idea
amistre64
  • amistre64
I have an idea too, but the question still makes no real sense we can determine the number of points remaining after each submission, if .10 is used, we have .90 remaining submission 0: 20 submission 1: 20 (.90) submission 2: (20 (.90))(.90) submission 3: (20 (.90)(.90))(.90) ... right?
chaotic_butterflies
  • chaotic_butterflies
I don't know if this has to do with anything but virtual school allows its students to retake tests if they need to, and they can reset it however many times until they have reached a certain amount of retakes. Each retake isn't influenced by the other... so if Drake is trying to get extra credit and he isn't satisfied with what he has, then he could reset and test himself on only the portion he got wrong - basically what all that rambling meant is that each retake probably doesn't influence another, I don't know if that's helpful or not it sounded better in my head
chaotic_butterflies
  • chaotic_butterflies
What you said sounds more logical than what I just spewed out.
amistre64
  • amistre64
the thing is, it says he can make changes and receive .10 of the missing points back. it does not say: "up to" .10 it does not say: "correct changes" it does not say: anything at all to me
amistre64
  • amistre64
the remaining points after 10 submissions looks to be 20(.90)^(10)
amistre64
  • amistre64
but that isnt a series, its not a summation process that is being asked for.
chaotic_butterflies
  • chaotic_butterflies
And this is why it's so important to have a physical math teacher for high school math, I used to actually know what on earth I was doing...
amistre64
  • amistre64
score0 = 80 score1 = 80 + 20(.10) score2 = 80 + 20(.10) + 20(.90)(.10) score3 = 80 + 20(.10) + 20(.90)(.10) + 20(.90)(.90)(.10) this is what its looking at in my head ...
amistre64
  • amistre64
adding on 10% of the 90% thats left over from the previous submission
amistre64
  • amistre64
it actually gets us to the same amount as the sequence setup
chaotic_butterflies
  • chaotic_butterflies
So should I go with that and assume the he gets the highest score on all of the tries to see what his maximun should be? I mean I guess I could do that but technically it's not creating a overall function
chaotic_butterflies
  • chaotic_butterflies
Sequence setup?
amistre64
  • amistre64
its creating it, you just have to see it for what it is. we an form a function from it
amistre64
  • amistre64
sequence is a list series is a summation of the terms in a list.
chaotic_butterflies
  • chaotic_butterflies
I understand that much, but I don't know what you're meaning
amistre64
  • amistre64
20(.90)^n gives us a list of values depending on n 20(.90)^10 = 6.97 which is the remaining points that cannot be claimed since its been submitted 10 times.
amistre64
  • amistre64
100 - 6.97 is the maximum score they can obtain.
amistre64
  • amistre64
the actual score process: score1 = 80 + 20(.10)(.90)^0 score1 = 80 + 20(.10)(.90)^0 + 20(.10)(.90)^1 score2 = 80 + 20(.10)(.90)^0 + 20(.10)(.90)^1+ 20(.10)(.90)^2 each score is a term, but part of it is also the summation of a geometric series. score n = 80 + 20(.10)(.90)^0 + 20(.10)(.90)^1+...+ 20(.10)(.90)^(n-1) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ this is a geometric series
amistre64
  • amistre64
do you know the formula for a geometric series?
chaotic_butterflies
  • chaotic_butterflies
No Sir (or M'am)
amistre64
  • amistre64
then all this harder processing has been rather in vain dont you think ..
amistre64
  • amistre64
find the formula for the sum of a geometric series for me ..
chaotic_butterflies
  • chaotic_butterflies
If you're asking me if I don't understand anything that you've shared with me, I've gotten the basic gist of it. I'll go look for that formula.
amistre64
  • amistre64
our initial score is 80, which means there is 20 points missing we submit it and our score goes from 80, to 80 + 20(.10), and there is 20(.90) points left to plunder thru we submit it again and our score goes from 80 + 20(.10), to 80 + 20(.10) + 20(.90)(.10) and there is 20(.90)(.90) points left to plunder thru we submit it again and our score goes from 80 + 20(.10) + 20(.90)(.10) to 80 + 20(.10) + 20(.90)(.10) + 20(.90)(.90)(.10) and there is 20(.90)(.90)(.90) points left to plunder thru etc etc etc
chaotic_butterflies
  • chaotic_butterflies
I found yhe formula I think and it's terrifying
1 Attachment
amistre64
  • amistre64
lol, that A formula, but thats the summation of an arithmetic series we want:\[S=g_1\frac{1-r^n}{1-r}\]
chaotic_butterflies
  • chaotic_butterflies
That's a little less scary but what do the letters stand for ?
amistre64
  • amistre64
g1 is a constant term, its a common factor among the setup forget the 80, what is the common factor of the rest of it?
chaotic_butterflies
  • chaotic_butterflies
1/10...?
amistre64
  • amistre64
80 + 20(.10)(.90)^0 + 20(.10)(.90)^1+...+ 20(.10)(.90)^(n-1) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ each term in the underlined part has 20(.10) in common, we can factor them out 80 + 20(.10) [(.90)^0 + (.90)^1+...+ (.90)^(n-1)] ^^^^^^^^^^^^^^^^^^^^^^^^^^ this is our series in terms of its ratio g1 = 20(.10) what is r?
chaotic_butterflies
  • chaotic_butterflies
I've gotten to the point where I have to say the dreaded "I have no idea.."
amistre64
  • amistre64
hint: ratio starts with an 'r' the setup in terms of our common ratio is: (.90)^0 + (.90)^1+...+ (.90)^(n-1) what is now common among this?
chaotic_butterflies
  • chaotic_butterflies
(.90)
amistre64
  • amistre64
correct :) so, g1 = 20(.10) r = .90 what is n?
amistre64
  • amistre64
n = 1-, the number of submission we are allowed to make ... \[score_{n}=80+g_1~\frac{1-r^n}{1-r}\] \[score_{10}=80+20(.10)\frac{1-.90^{10}}{1-.90}\] which is the same value as the more simpler route: \[score_{10}=100-20(.90)^{10}\]
amistre64
  • amistre64
n=10
amistre64
  • amistre64
im going to run an errand now, so good luck, ask about what it is you are still concerned with.
chaotic_butterflies
  • chaotic_butterflies
Alright, thank you very much!

Looking for something else?

Not the answer you are looking for? Search for more explanations.