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TheQube1
 one year ago
I need help with this Geometry PLEASE.
I'm not asking for just the answer but how to go about finding it.
I will Fan and Medal Best responders
TheQube1
 one year ago
I need help with this Geometry PLEASE. I'm not asking for just the answer but how to go about finding it. I will Fan and Medal Best responders

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What's the question?

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0Here is the question @lexiladybug22 @Here_to_Help15

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0@Here_to_Help15 are you in geometry B? and do you know this lesson?

Here_to_Help15
 one year ago
Best ResponseYou've already chosen the best response.0Ok good um i need help actually ;) and yes i am

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0Dang lol you on the final to?

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0oh well that is what this is.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1which part are you working on ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433182139371:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1check whether the below proportion holds\[\large \dfrac{AC}{EC}~~\stackrel{?}{=}~~\dfrac{BC}{DC}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \dfrac{12}{9}~~\stackrel{?}{=}~~\dfrac{20}{15}\] \[\large \dfrac{4}{3}~~\stackrel{?}{=}~~\dfrac{4}{3}\] which is true, therefore \(\triangle ABC \sim \triangle EDC\) is true

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Just like there is SAS for proving two triangles congruent, there is a version of SAS for proving two triangles similar. SAS Similarity is: if the lengths of two sides of a triangle are proportional to corresponding parts of another triangle, and the included angles are congruent, then the triangles are similar.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Above, @ganshie8 showed that the lengths of the sides are proportional. From the figure, you see that angles ACB and ECD are vertical, making them congruent. This is what you need for SAS Similarity to work, and the triangles are similar.

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 so using SAS similarity is ow I find out that problem?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Using SAS Similarity allows you to answer part (A). You can say that the triangles are similar, and the reason is SAS Similarity, since there is a pair of congruent corresponding angles, and this pair of angles are included by two pairs of corresponding sides whose lengths are proportional. All of this is part (A).

TheQube1
 one year ago
Best ResponseYou've already chosen the best response.0what about part (B) and (C)? @mathstudent55
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