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anonymous

  • one year ago

Hi, my question is how do you square a quantity like (2sqrt11)^2

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  1. johnweldon1993
    • one year ago
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    \[\large (2\sqrt{11})^2\] we can write it as \[\large 2\sqrt{11} \times 2\sqrt{11}\] So what is 2 times 2? and what is √11 times √11?

  2. anonymous
    • one year ago
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    2x2=4, I'm not sure what the square root of 11 x square root of 11 is

  3. johnweldon1993
    • one year ago
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    Well...we know √11 times √11 can be written as \[\large \sqrt{11}^2\] right? "The square of a square root" they cancel each other out So the square root on 11 times the square root of 11 = 11 so this question becomes \(\large 4\times 11\)

  4. anonymous
    • one year ago
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    but wouldn't it go like 4+2sqrt11+2sqrt11+sqrt11^2?

  5. johnweldon1993
    • one year ago
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    Nope....if it were \[\large (2 + \sqrt{11})^2\] it would be that case! because you would distribute it out! however this is just multiplication \[\large (2\sqrt{11})^2\]

  6. anonymous
    • one year ago
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    oh ok, that makes sense.

  7. anonymous
    • one year ago
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    Another question I have is that it says to multiply and simplify. (7 3sqrt4)(6 3sqrt2)

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