anonymous
  • anonymous
Divide and simplify completely.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1433180002271:dw|
anonymous
  • anonymous
ok!
anonymous
  • anonymous
okay! thank you so much!!:D

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More answers

anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
@paki
Luigi0210
  • Luigi0210
Start by factoring then changing that division to multiplication.
anonymous
  • anonymous
can we do it on the drawing tool?
anonymous
  • anonymous
@Luigi0210
Luigi0210
  • Luigi0210
Sure, like I said, start factoring, what do you get?
anonymous
  • anonymous
do i start with writing the whole problem? orjust the first two fractions?
Luigi0210
  • Luigi0210
Writing the whole problem would be better, it'll help see where things might cancel.
anonymous
  • anonymous
okay! sorry i took long! i had to login again1:) @Luigi0210
anonymous
  • anonymous
|dw:1433181469815:dw|
anonymous
  • anonymous
@Luigi0210
Luigi0210
  • Luigi0210
Okay, so start by changing the division to multiplication, do you know how?
anonymous
  • anonymous
@Luigi0210 i had to change laptobs, so there will be no more lagging!
Luigi0210
  • Luigi0210
Alright, so do you know how to change the operations from division to multiplication?
anonymous
  • anonymous
im not so sure! @Luigi0210
Luigi0210
  • Luigi0210
Alright, so in order to switch it, you flip the fraction and then change the sign, like so: \(\large \frac{a}{b} \div \frac{c}{d}\) becomes \(\large \frac{a}{b} \times \frac{d}{c} \) make sense?
anonymous
  • anonymous
yes
Luigi0210
  • Luigi0210
Alright, try applying it to this part: \(\large \frac{6x+6}{x^2-1} \times \color{green}{\frac{x-1}{8x^2-24x} \div \frac{24}{x^2-9}} \)
anonymous
  • anonymous
ok |dw:1433183061134:dw|
Luigi0210
  • Luigi0210
Right, now let's start factoring, what these factor to: \(\large x^2-1=\) \(\large 6x+6=\) \(\large 8x^2-24x=\) \(\large x^2-9=\)
anonymous
  • anonymous
|dw:1433183782053:dw|
anonymous
  • anonymous
@Luigi0210
Nnesha
  • Nnesha
apply difference of square method a^2 - b^2 = (a+b)(a-b)
Nnesha
  • Nnesha
so x^2 - 9 = ?
anonymous
  • anonymous
@Nnesha
Nnesha
  • Nnesha
yes ?
anonymous
  • anonymous
im not sure what that equals to?
Nnesha
  • Nnesha
difference of square take square root of first term and 2nd term write in two parentheses (sqr root of first term + square root of 2nd term ) ( sqr root of first term - square root of 2nd term) a^2 - b^2 = (a+b)(a-b)
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
so x^2 - 9 = ?
anonymous
  • anonymous
|dw:1433185790534:dw|
anonymous
  • anonymous
@Nnesha
Nnesha
  • Nnesha
|dw:1433185969475:dw| take square root of both terms
anonymous
  • anonymous
|dw:1433186021089:dw|
Nnesha
  • Nnesha
what is square root of 9 ?
anonymous
  • anonymous
|dw:1433186054040:dw|
Nnesha
  • Nnesha
yes that's right
Nnesha
  • Nnesha
\(\huge\rm \frac{6x+6}{x^2-1} \times \color{green}{\frac{x-1}{8x^2-24x} \div \frac{24}{x^2-9}} \) alright first of change division to multiplication
Nnesha
  • Nnesha
http://prntscr.com/7bz6e6 <---
anonymous
  • anonymous
|dw:1433186323191:dw|
Nnesha
  • Nnesha
ys right
Nnesha
  • Nnesha
i have to go i'll be here after 15 mints
anonymous
  • anonymous
|dw:1433186435230:dw|
anonymous
  • anonymous
@Nnesha
anonymous
  • anonymous
@Luigi0210
anonymous
  • anonymous
|dw:1433186564993:dw|
Nnesha
  • Nnesha
|dw:1433186742147:dw| now factor 6x-6 x^2 -1 8x^2 -24x
anonymous
  • anonymous
@Nnesha how do i do that?
anonymous
  • anonymous
@Michele_Laino @Nnesha
Nnesha
  • Nnesha
same method for x^2-1 difference of square
anonymous
  • anonymous
how do i do that? can you show me on the drawing tool????
Nnesha
  • Nnesha
it's same like last one square root of first number and square root of 2nd number
Nnesha
  • Nnesha
|dw:1433188107357:dw| just like this one
anonymous
  • anonymous
with what numbers?
Nnesha
  • Nnesha
x^2 - 1 first term is x^2 2nd term is 1
anonymous
  • anonymous
|dw:1433188199277:dw|
Nnesha
  • Nnesha
|dw:1433188239145:dw| take SQUARE ROOT of first and last term what is square root of x^2 ?
anonymous
  • anonymous
|dw:1433188302499:dw|
Nnesha
  • Nnesha
square root of 1 is just one
anonymous
  • anonymous
|dw:1433188379947:dw|
Nnesha
  • Nnesha
yes right (x +1 ) (x-1)
anonymous
  • anonymous
ok
Nnesha
  • Nnesha
\(\huge\rm \frac{6x+6}{(x+1)(x-1)} \times \color{green}{\frac{x-1}{8x^2-24x} \times \frac{24}{(x-3)(x+3)}} \) now factor 6x+6 what is commin in these both term ?
anonymous
  • anonymous
they both have 6
Nnesha
  • Nnesha
yes right take it out
Nnesha
  • Nnesha
6x+6 6( ) what should go in the parentheses ?
anonymous
  • anonymous
so you are left with x?
Nnesha
  • Nnesha
nope divide both term by 6 so 6/6 = ?
anonymous
  • anonymous
2
Nnesha
  • Nnesha
6 divide by 6 = ?
anonymous
  • anonymous
is 1
Nnesha
  • Nnesha
yes right so it's 6(x+1)
Nnesha
  • Nnesha
\(\huge\rm \frac{6(x+1)}{(x+1)(x-1)} \times \color{green}{\frac{x-1}{8x^2-24x} \times \frac{24}{(x-3)(x+3)}} \) ahh last one factor 8x^2 -24x
anonymous
  • anonymous
what whould it be for 8x^2?
Nnesha
  • Nnesha
x^2 ? lowest degree of x would be common term and yes 8 is right and what else ?
anonymous
  • anonymous
ok
anonymous
  • anonymous
what about for 24!
Nnesha
  • Nnesha
yes so 8 is common what about variable ?
anonymous
  • anonymous
the variable is x!
Nnesha
  • Nnesha
yes right so 8x is out what should goe in parentheses ??
anonymous
  • anonymous
umm im not sure?
Nnesha
  • Nnesha
|dw:1433189936138:dw| divide both term by 8x
anonymous
  • anonymous
so x and 3?
Nnesha
  • Nnesha
yep right
anonymous
  • anonymous
yayy!!!
Nnesha
  • Nnesha
wait
Nnesha
  • Nnesha
it's \(\huge\rm \frac{6(x+1)}{(x+1)(x-1)} \times \color{green}{\frac{x-1}{8x(x-3)} \times \frac{(x-3)(x+3)}{ 24}} \) start canceling stufffff
anonymous
  • anonymous
|dw:1433190165667:dw|
Nnesha
  • Nnesha
\(\huge\rm \frac{6\cancel{(x+1)}}{\cancel{(x+1)}\cancel{(x-1)}} \times \color{green}{\frac{\cancel{x-1}}{8x\cancel{(x-3)}} \times \frac{\cancel{(x-3)}(x+3)}{ 24}} \) \[\frac{ 6(x+3) }{ 8x \times 24 }\] 6/24 ?
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1433190834800:dw|
Nnesha
  • Nnesha
nopw that's not a pllus sgn
Nnesha
  • Nnesha
|dw:1433190954018:dw|reduse the fraction
Nnesha
  • Nnesha
reduce *
anonymous
  • anonymous
1/4
anonymous
  • anonymous
for some reason it whould not post but, i got it!!
Nnesha
  • Nnesha
\(\huge\rm \frac{6\cancel{(x+1)}}{\cancel{(x+1)}\cancel{(x-1)}} \times \color{green}{\frac{\cancel{x-1}}{8x\cancel{(x-3)}} \times \frac{\cancel{(x-3)}(x+3)}{ 24}} \) \[\frac{ 1(x+3) }{ 8x \times 4 }\] now multiply
Nnesha
  • Nnesha
4 times 8x = ? done!
anonymous
  • anonymous
32x ! @Nnesha
Nnesha
  • Nnesha
yep right x+3/32x
anonymous
  • anonymous
so the answer is c? @Nnesha
Nnesha
  • Nnesha
where are the answer choices ?

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