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anonymous

  • one year ago

what is the change of entropy for a heat engine using 500.0 J at 20.0°C ? 0.04 J/K , 0.25 J/K , 0.59 J/K , or 1.71 J/K ? :/

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  1. Michele_Laino
    • one year ago
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    it is simple, we have to apply this formula: \[S = \frac{{\Delta Q}}{T}\]

  2. anonymous
    • one year ago
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    okay! 500/20 ? = 25? so our solution would be 0.25 J/K ?

  3. Michele_Laino
    • one year ago
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    no, we have to compute the absolute temperature first: T =20+273=293 °K

  4. anonymous
    • one year ago
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    ohh okay! so 500/293 = 1.706? so our solution is 1.71 J/K ?

  5. Michele_Laino
    • one year ago
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    yes! that's right!

  6. anonymous
    • one year ago
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    yay! thank you!!

  7. Michele_Laino
    • one year ago
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    :)

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