A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

A lead fishing weight with a mass of 57 g absorbs 146 cal of heat. If its initial temperature is 45∘C, what is its final temperature?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So far I have:\[146cal = 57g * C *(T _{f}-45)\]\[146\cal = 610.864J\] so:\[610.864 = 57g * C * (T _{f}-45)\] but where do i go from here? how do i find C and or Tf?

  2. JoannaBlackwelder
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    It is given in the problem that we are dealing with a lead weight. So, we need to use the heat capacity for lead in consistent units.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.