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anonymous

  • one year ago

any who helps I will give a medal! 1. Provide a counterexample that shows the statement is false. Explain why the counterexample makes the statement false. If two fractions have unlike denominators, then the LCD is the product of their denominators

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. misty1212
    • one year ago
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    HI!!

  3. misty1212
    • one year ago
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    do you know what you are being asked to do?

  4. anonymous
    • one year ago
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    LCD of a/b and c/d is given by LCD(a,c)/LCM(b,d). Consider example, 5/6 and 4/15. Here LCD=LCD(5,4)/LCM(6,15)=1/30. However, the product of their denominators is 60. This is a counter example.

  5. anonymous
    • one year ago
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    LCD of a/b and c/d is given by LCD(a,c)/LCM(b,d). Consider example, 5/6 and 4/15. Here LCD=LCD(5,4)/LCM(6,15)=1/30. However, the product of their denominators is 60. This is a counter example.

  6. anonymous
    • one year ago
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    no can you help me @misty1212

  7. misty1212
    • one year ago
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    ok sure

  8. misty1212
    • one year ago
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    If two fractions have unlike denominators, then the LCD is the product of their denominators you want a "counter example" that means you want an example of two fractions with unlike denominators where the least common multiple of the denominators is NOT their produce

  9. misty1212
    • one year ago
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    so for example if the denominators had a common factor, like 4 and 12, then the least common multiple of 4 and 12 is just 12, not \(4\times 12\) that is all you need for a "counter example"

  10. misty1212
    • one year ago
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    in simple english you have to provide an example of two fractions whose least common denominator is NOT found by multiplying the denominators together

  11. anonymous
    • one year ago
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    ok

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