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Just use logic. Test out numbers and see which ones fit.
ya I was going to do that but I its not multiple choice and I'm not sure how to use matrices to solve the problem...
It doesn't need to be multiple choice. I already figured out what x, y, and z are just by using logic.
I'll give you a couple of tips. In the second line, you notice that 4x and 5y added only get 3, so that means either x or y is negative. In the third line, you notice that y minus-3 times z is -10 so that means y is a small number and z is definitely positive.
I know but I have to write out each step using matrices to get credit...
hate systems like that
ya me too... anyway thanks for trying to help
this is very long and annoying you have to use some sort of elimination
i would cheat if it was me
you can multiply the first equation by \(-4\) and add it to the second that will eliminate the \(x\) terms, then you will be left with two equations and two unknowns
You didn't read my previous comment did you? I have to show my work with the matrices to get credit
\[-4x-4y-4z=-16\\ 4x+5y=3\] add and get oh i see are you supposed to row reduce the matrix? it is really the same thing exactly
I'm not sure...