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anonymous

  • one year ago

Find 7 values of y=5x+2?

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    i think all you need to do is pick 7 numbers for x and plug them in

  3. misty1212
    • one year ago
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    for example if you pick \(x=0\) then you get \(y=0+2=2\) and if you pick \(x=1\) you get \(y=5\times 1+2=7\) and so on

  4. misty1212
    • one year ago
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    the truth is of course that \(y\) can be any number, so it is not really clear what it means "find 7 values of y"

  5. anonymous
    • one year ago
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    what @misty1212 said y can be anything is that the exact way the question is written or are you supposed to write maybe 7 ordered pairs like \[(0,2),(1,7),(2,12)...\]

  6. anonymous
    • one year ago
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    i think seven ordered pairs

  7. anonymous
    • one year ago
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    @satellite73

  8. anonymous
    • one year ago
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    because it wants me to put it in a table then on a graph

  9. misty1212
    • one year ago
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    ok then do what misty said

  10. misty1212
    • one year ago
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    lol

  11. misty1212
    • one year ago
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    did you get the \((0,2)\) part?

  12. anonymous
    • one year ago
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    sorta

  13. misty1212
    • one year ago
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    the equation is \[y=5x+2\] right?

  14. anonymous
    • one year ago
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    yes

  15. misty1212
    • one year ago
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    ok so if \(x\) is \(0\) we get \[y=5\times 0+2=2\] right?q

  16. anonymous
    • one year ago
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    yes

  17. misty1212
    • one year ago
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    that means the ordered pair is \((0,2)\)

  18. misty1212
    • one year ago
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    now lets let \(x=1\) we get \(y=5\times 1+2=7\)

  19. misty1212
    • one year ago
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    so another ordered pair would be \((1,7)\) ok so far?

  20. anonymous
    • one year ago
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    okay

  21. misty1212
    • one year ago
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    how about if \(x=2\) what is \(y\) then ?

  22. anonymous
    • one year ago
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    12

  23. misty1212
    • one year ago
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    ok good now we have 3 ordered pairs \[(0,2),(1,7),(2,12)\] all you need is four more ....

  24. anonymous
    • one year ago
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    oh okay i get it wow im slow haha sorry but thank you alot

  25. misty1212
    • one year ago
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    lol it is not like you are born knowing it, but you are right, it is not that hard \[\huge \color\magenta\heartsuit\]

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