anonymous
  • anonymous
Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this interval, cycle A has an average acceleration of 2.0 m/s^2 due east, while cycle B has an average acceleration of 4.0 m/s^2 due east. By how much did the speeds differ at the beginning of the four-second interval?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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KendrickLamar2014
  • KendrickLamar2014
8 m/s. They have a difference of 2m/s^2 acceleration. So every second backwards, Bike B was traveling 2m/s slower than Bike A. So 4 seconds ago, Bike B was moving 8 m/s slower than Bike A. Bike A was moving faster. An interesting side note - the problem doesn't state anything about the positions of the bikes, so even though after 4 seconds they are traveling the same VELOCITY, they could be miles apart. I would have liked to see a bonus question like, "Which bike will be in the lead after 4 more seconds?" or something like that to try to trick you. The answer would be, "Not enough information to know". Resources: https://answers.yahoo.com/question/index?qid=20070829203434AAbimhw#
The_Beast_Eli
  • The_Beast_Eli
What He said XD
KendrickLamar2014
  • KendrickLamar2014
^

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