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cutiecomittee123
 one year ago
how do find the vertex and foci of this hyperbola
(x2)^2/36  (y+1)^2/64 =1
cutiecomittee123
 one year ago
how do find the vertex and foci of this hyperbola (x2)^2/36  (y+1)^2/64 =1

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1standard form is \[\frac{(xh)^2}{a^2}+\frac{(yk)^2}{b^2}=1\] you get the center with your eyeballs right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1this is where you say "yes i see it" or "no i have no clue"

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok what is the center?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok good now we need to know one other thing what does it look like left or right?dw:1433186027332:dw

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0second, its horizontal

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the \(x\) term comes first, vertical

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1now that we (presumably) have these two facts, the orientation and the center, the rest is easy

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the center is \((2,1)\) and it is vertical that means the vertices are to the LEFT and RIGHT of the center (that is why we need the orientation first)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1if it was horizontal they would be up and down

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0okay makes sense.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you have \[\frac{(x2)^2}{36}\frac{(y+1)^2}{64}=1\] which looks like \[\frac{(xh)^2}{a^2}+\frac{(yk)^2}{b^2}=1\] what is \(a\)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1right so how easy is this? the vertices are 6 units to the right and left of \((2,1)\)

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0okay so (8, 1) and (5, 1)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1hmm no to the second one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh no no to both of them

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1what is 6 units to the left of \((2,1)\)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1or is simple english , what is \(26\) and \(2+6\)?

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0oh lol. (4,1) and (8,1)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok that takes care of the vertices now for the foci

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0alright so how do we find the foci?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1we need one number number , namely \(c\) and we find it like pythagoras \[a^2+b^2=c^2\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you got \(a^2=36,b^2=64\) what is \(c\)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1right and so \(c^2=100\) making \(c=?\)

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0well + or  10

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so now (don't mess this up!) what is ten units to the right and left of \((2,1)\)?

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0(12,1) and (8,1)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i know what you meant (i hope)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[(12,1)\] is ten units the the right, \[(\color{red}8,1)\] is ten units to the left

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is really not that hard people here don't like it and math teachers make it seem way harder than it is you see we really only needed two things the center and the orientation

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0yeah it seems simple

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\color\magenta\heartsuit\]
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