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anonymous

  • one year ago

Can someone explain to me how to factor 3x^2y^2-2xy^2-8y^2?

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  1. anonymous
    • one year ago
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    \[3x^2y^2-2xy^2-8y^2\]

  2. anonymous
    • one year ago
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    @Preetha

  3. misty1212
    • one year ago
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    HI!!

  4. misty1212
    • one year ago
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    to start with each term has a common factor of \(y^2\) right? so you can "factor it out" as the math teachers say

  5. misty1212
    • one year ago
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    got that part?

  6. anonymous
    • one year ago
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    |dw:1433188051883:dw| would this be it?

  7. misty1212
    • one year ago
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    well that is a start, yes maybe we can also factor \[(3x^2-2x-8)\]

  8. anonymous
    • one year ago
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    How?

  9. misty1212
    • one year ago
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    idk i suck at factoring maybe \[(3x+?)(x+?)\]

  10. misty1212
    • one year ago
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    try \[(3x+4)(x-2)\]

  11. anonymous
    • one year ago
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    so \[y^2(3x-4)(x-2)\]

  12. misty1212
    • one year ago
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    no

  13. misty1212
    • one year ago
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    \[y^2(3x+4)(x-2)\]

  14. anonymous
    • one year ago
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    Oops, I meant to put the + sign

  15. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

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