anonymous
  • anonymous
Fan and medal! Triangle ABC is similar to triangle DEF. Using the image below, prove that lines BC and EF have the same slope. You must show all of your work to receive credit.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
lizz123
  • lizz123
Step 1: Find the points for B, C , E, and F.
anonymous
  • anonymous
B -2,4 C 1,1 E 4,4 F 6,2 @lizz123

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lizz123
  • lizz123
yes your correct.
lizz123
  • lizz123
Do you know how to use: \[y=\frac{ y2-y1 }{ x2- x1 }\]
lizz123
  • lizz123
You can use BC first or EF first
anonymous
  • anonymous
No, please explain this to me
anonymous
  • anonymous
lizz123
  • lizz123
ok using the points you just used there is an x and y part
lizz123
  • lizz123
so using the points for B which: B= -2, 4 x will be -2 y will be 4
lizz123
  • lizz123
so that will help you fill it in the formula.
lizz123
  • lizz123
Technically the points from B= -2,4 it would be written like this x1=-2 y1=4
lizz123
  • lizz123
Do C but instead of using x1 and y1 you have to use x2 and y2 so you can use two other numbers for x and y 2
anonymous
  • anonymous
y=y2−4/x2+2
anonymous
  • anonymous
y=1−4/1+2
anonymous
  • anonymous
campbell_st
  • campbell_st
look at triangle ABC what is the length of AB what is the length of AC...?
campbell_st
  • campbell_st
AB is rise and AC is run Slope = rise/run
OregonDuck
  • OregonDuck
A = (-5, 8) C = (-11, 2) x1 y1 x2 y2 slope = Y2-Y1 / X2-X1 = 2-8 / -11--5 = -6/ -11+5 = -6/-6 = 1
anonymous
  • anonymous
B -2,4 C 1,1 E 4,4 F 6,2 ABC= 4.5 EFD= 2 @campbell_st that's all I know so far @OregonDuck
anonymous
  • anonymous
@OregonDuck could you please explain to me how you got that? ):
anonymous
  • anonymous
@Nnesha @perl @Loser66 @sammixboo @pooja195 @uri @Michele_Laino @Champion @geerky42 @Preetha @shifuyanli @Data_LG2 @tHe_FiZiCx99 @myko @Love_Ranaa Mathlete @Mehek14 Im really need some help I've been on this question for like two hours
anonymous
  • anonymous
you just have to continue what you were doing :) this for the slope of BC: m=1−4/1+2 what did you get when you solve that?
anonymous
  • anonymous
m= -3/3 m= -1 Is this right? @Data_LG2
anonymous
  • anonymous
yes. Now do the same thing with EF
anonymous
  • anonymous
y=2−4/6-4 -2/2 -1 @Data_LG2
anonymous
  • anonymous
right :) Do EF and BC have the same slope?
anonymous
  • anonymous
Yes off they're both -1!
anonymous
  • anonymous
ofc*
anonymous
  • anonymous
exactly :) your proof will be your solution in solving their slopes and you're done with it

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