anonymous
  • anonymous
An urn contains seven red balls, seven white balls, and seven blue balls, and sample of five balls is drawn at random without replacement. Compute the probability that all of the balls in the sample are the same color. (Round your answer to four decimal places.)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I have half of the answer. C (21,5) = 20,349 do I multiply by 3? i also need to use C (7,5) = 21 I thought the answer was \[\frac{ 5 \times 21 }{20,349}\approx0.0051\] But it is wrong
anonymous
  • anonymous
all of the same color means "all red OR all white OR all blue"
anonymous
  • anonymous
so \[3\times \frac{\binom{7}{5}}{\binom{21}{5}}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
oh yeah sorry i didn't read carefully YES multiply by 3
campbell_st
  • campbell_st
permutation problem rather than a combination problem since the balls aren't replaced
anonymous
  • anonymous
?
anonymous
  • anonymous
you get the same answer no matter which way you go it
anonymous
  • anonymous
\[\frac{7\times 6\times 5\times 4\times 3}{21\times 20\times 19\times 18\times 16}\]same as \[\frac{\binom{7}{5}}{\binom{21}{2}}\]
anonymous
  • anonymous
thank you I will calculate right now
anonymous
  • anonymous
you can just multiply your answer above by 3
anonymous
  • anonymous
I got 0.3999 and it was wrong. :_(
anonymous
  • anonymous
I got it!!! =0.0031
anonymous
  • anonymous
thank you for all your help Satellite73

Looking for something else?

Not the answer you are looking for? Search for more explanations.