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1. anonymous

-1/x-6

2. anonymous

That's not an option. The options are: 1/6-x where x=0,6 1/6-x where x=6 1/6x where x = 0 1/6

3. anonymous

is it x/(6x-x^2)

4. anonymous

or is the -x^2 not part of the fraction

5. anonymous

1/6-x where x=6

6. anonymous

It is x over 6x-x^2 this is the entire fraction

7. IrishBoy123

lmLtfy $$\frac{x}{ 6x-x^2}$$ so try losing an 'x', ie divide top and bottom by x

8. anonymous

So, I would get 1/6-x ; where x= 6 ????

9. anonymous

@IrishBoy123

10. anonymous

correct

11. IrishBoy123

$$\frac{x}{6x-x^2} = \frac{x}{x}.\frac{1}{6-x} = \frac{1}{6-x}$$ well done

12. anonymous

you're sure, that I am right? answer says: $1 / 6-x ; x \neq 6$

13. anonymous

@IrishBoy123

14. IrishBoy123

yes

15. anonymous

I posted another question! I really need help. I do not understand this