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You mean to use the n as an exponent?
If so, do you mean the pattern: \(4 \cdot 3^n\)

yes!

12

144?

36

Exactly:
\(4 \cdot 3^2 = 4 \cdot (3 \times 3) = 4 \times 9 = 36\)

ok so the next is 4 x 3^3

Yes, that's it.

108 is what I got

so a.

Correct.
Now use n = 4 to do the 4th term.

ok

would you mind helping with one more

No. Wait.

ok

oh its c

Correct!

ok thank you

What is the third term in the pattern with formula 8 · 4n – 1?
A.
64
B.
96
C.
128
D.
512

I dont get the - 1 part

ohh minus 1

nvm

Wait. Once again, we first need to understand this.
I am assuming n - 1 is an exponent, right?

yes

This:
\(8 \cdot 4^{n - 1} \)

yes

512

You calculated it correctly, but I made a mistake.

You are asked for the third term.
Just do the same but let n = 3, not 4.

ok

\(8 \cdot 4^{3 - 1} = 8 \cdot 4^2\)
This is the correct one.

ok its c

128

yay I got 100 gtg

Yes, C is correct, 128.