What are the first four terms in the multiplication pattern given by the formula? 4 · 3n A. 4, 12, 36, 108 B. 7, 21, 63, 189 C. 12, 36, 108, 324 D. 12, 24, 36, 48 WILL MEDAL AND FAN:)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

What are the first four terms in the multiplication pattern given by the formula? 4 · 3n A. 4, 12, 36, 108 B. 7, 21, 63, 189 C. 12, 36, 108, 324 D. 12, 24, 36, 48 WILL MEDAL AND FAN:)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

You mean to use the n as an exponent? If so, do you mean the pattern: \(4 \cdot 3^n\)
yes!
You are looking for the first 4 terms. In these patterns, the way they work, is you let n = 1, then n = 2, then n = 3, and so on. For each of those values of n, evaluate the expression. Let's start with n = 1. What is \(4 \cdot 3^1= \)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

12
A number raised to the 1 power is the number itself. So you are correct. That is the first number in the pattern. Now let n = 2. What is 4 * 3^2 =
144?
A number raised to the second power, called the square of a number, is the number multiplied by itself.
No. You need to be careful with the order of operations. You must do the exponent first. The exponent is only on the 3, not on 4 * 3. First do 3^2. What do you get? Then multiply that result by 4.
36
Exactly: \(4 \cdot 3^2 = 4 \cdot (3 \times 3) = 4 \times 9 = 36\)
ok so the next is 4 x 3^3
Now you can do the same pattern for n = 3. The exponent is 3, and you are just raising the 3 to the power 3. Then multiply by 4.
Yes, that's it.
108 is what I got
so a.
Correct. Now use n = 4 to do the 4th term.
ok
would you mind helping with one more
No. Wait.
ok
The answer is not A. Remember, we have so far 12, 36, 108. There is only one choice that starts with those numbers.
oh its c
Correct!
ok thank you
What is the third term in the pattern with formula 8 · 4n – 1? A. 64 B. 96 C. 128 D. 512
I dont get the - 1 part
ohh minus 1
nvm
Wait. Once again, we first need to understand this. I am assuming n - 1 is an exponent, right?
yes
This: \(8 \cdot 4^{n - 1} \)
yes
Here you only need the 4th term. The 4th term has n = 4, since we start with n = 1. Let n be 4. Then the exponent is 4 - 1 = 3
512
The given pattern: \(8 \cdot 4^{n - 1} \) For n = 4: \(8 \cdot 4^{4 - 1} = 8 \cdot 4^3 \) Now calculate 4^3 and multiply by 8.
You calculated it correctly, but I made a mistake.
You are asked for the third term. Just do the same but let n = 3, not 4.
ok
\(8 \cdot 4^{3 - 1} = 8 \cdot 4^2\) This is the correct one.
ok its c
128
yay I got 100 gtg
Yes, C is correct, 128.

Not the answer you are looking for?

Search for more explanations.

Ask your own question