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anonymous
 one year ago
What are the first four terms in the multiplication pattern given by the formula?
4 · 3n
A.
4, 12, 36, 108
B.
7, 21, 63, 189
C.
12, 36, 108, 324
D.
12, 24, 36, 48
WILL MEDAL AND FAN:)
anonymous
 one year ago
What are the first four terms in the multiplication pattern given by the formula? 4 · 3n A. 4, 12, 36, 108 B. 7, 21, 63, 189 C. 12, 36, 108, 324 D. 12, 24, 36, 48 WILL MEDAL AND FAN:)

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You mean to use the n as an exponent? If so, do you mean the pattern: \(4 \cdot 3^n\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You are looking for the first 4 terms. In these patterns, the way they work, is you let n = 1, then n = 2, then n = 3, and so on. For each of those values of n, evaluate the expression. Let's start with n = 1. What is \(4 \cdot 3^1= \)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1A number raised to the 1 power is the number itself. So you are correct. That is the first number in the pattern. Now let n = 2. What is 4 * 3^2 =

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1A number raised to the second power, called the square of a number, is the number multiplied by itself.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1No. You need to be careful with the order of operations. You must do the exponent first. The exponent is only on the 3, not on 4 * 3. First do 3^2. What do you get? Then multiply that result by 4.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Exactly: \(4 \cdot 3^2 = 4 \cdot (3 \times 3) = 4 \times 9 = 36\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so the next is 4 x 3^3

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Now you can do the same pattern for n = 3. The exponent is 3, and you are just raising the 3 to the power 3. Then multiply by 4.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Correct. Now use n = 4 to do the 4th term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you mind helping with one more

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The answer is not A. Remember, we have so far 12, 36, 108. There is only one choice that starts with those numbers.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the third term in the pattern with formula 8 · 4n – 1? A. 64 B. 96 C. 128 D. 512

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont get the  1 part

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Wait. Once again, we first need to understand this. I am assuming n  1 is an exponent, right?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1This: \(8 \cdot 4^{n  1} \)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Here you only need the 4th term. The 4th term has n = 4, since we start with n = 1. Let n be 4. Then the exponent is 4  1 = 3

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The given pattern: \(8 \cdot 4^{n  1} \) For n = 4: \(8 \cdot 4^{4  1} = 8 \cdot 4^3 \) Now calculate 4^3 and multiply by 8.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You calculated it correctly, but I made a mistake.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You are asked for the third term. Just do the same but let n = 3, not 4.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\(8 \cdot 4^{3  1} = 8 \cdot 4^2\) This is the correct one.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Yes, C is correct, 128.
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