anonymous
  • anonymous
What are the first four terms in the multiplication pattern given by the formula? 4 · 3n A. 4, 12, 36, 108 B. 7, 21, 63, 189 C. 12, 36, 108, 324 D. 12, 24, 36, 48 WILL MEDAL AND FAN:)
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathstudent55
  • mathstudent55
You mean to use the n as an exponent? If so, do you mean the pattern: \(4 \cdot 3^n\)
anonymous
  • anonymous
yes!
mathstudent55
  • mathstudent55
You are looking for the first 4 terms. In these patterns, the way they work, is you let n = 1, then n = 2, then n = 3, and so on. For each of those values of n, evaluate the expression. Let's start with n = 1. What is \(4 \cdot 3^1= \)

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anonymous
  • anonymous
12
mathstudent55
  • mathstudent55
A number raised to the 1 power is the number itself. So you are correct. That is the first number in the pattern. Now let n = 2. What is 4 * 3^2 =
anonymous
  • anonymous
144?
mathstudent55
  • mathstudent55
A number raised to the second power, called the square of a number, is the number multiplied by itself.
mathstudent55
  • mathstudent55
No. You need to be careful with the order of operations. You must do the exponent first. The exponent is only on the 3, not on 4 * 3. First do 3^2. What do you get? Then multiply that result by 4.
anonymous
  • anonymous
36
mathstudent55
  • mathstudent55
Exactly: \(4 \cdot 3^2 = 4 \cdot (3 \times 3) = 4 \times 9 = 36\)
anonymous
  • anonymous
ok so the next is 4 x 3^3
mathstudent55
  • mathstudent55
Now you can do the same pattern for n = 3. The exponent is 3, and you are just raising the 3 to the power 3. Then multiply by 4.
mathstudent55
  • mathstudent55
Yes, that's it.
anonymous
  • anonymous
108 is what I got
anonymous
  • anonymous
so a.
mathstudent55
  • mathstudent55
Correct. Now use n = 4 to do the 4th term.
anonymous
  • anonymous
ok
anonymous
  • anonymous
would you mind helping with one more
mathstudent55
  • mathstudent55
No. Wait.
anonymous
  • anonymous
ok
mathstudent55
  • mathstudent55
The answer is not A. Remember, we have so far 12, 36, 108. There is only one choice that starts with those numbers.
anonymous
  • anonymous
oh its c
mathstudent55
  • mathstudent55
Correct!
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
What is the third term in the pattern with formula 8 · 4n – 1? A. 64 B. 96 C. 128 D. 512
anonymous
  • anonymous
I dont get the - 1 part
anonymous
  • anonymous
ohh minus 1
anonymous
  • anonymous
nvm
mathstudent55
  • mathstudent55
Wait. Once again, we first need to understand this. I am assuming n - 1 is an exponent, right?
anonymous
  • anonymous
yes
mathstudent55
  • mathstudent55
This: \(8 \cdot 4^{n - 1} \)
anonymous
  • anonymous
yes
mathstudent55
  • mathstudent55
Here you only need the 4th term. The 4th term has n = 4, since we start with n = 1. Let n be 4. Then the exponent is 4 - 1 = 3
anonymous
  • anonymous
512
mathstudent55
  • mathstudent55
The given pattern: \(8 \cdot 4^{n - 1} \) For n = 4: \(8 \cdot 4^{4 - 1} = 8 \cdot 4^3 \) Now calculate 4^3 and multiply by 8.
mathstudent55
  • mathstudent55
You calculated it correctly, but I made a mistake.
mathstudent55
  • mathstudent55
You are asked for the third term. Just do the same but let n = 3, not 4.
anonymous
  • anonymous
ok
mathstudent55
  • mathstudent55
\(8 \cdot 4^{3 - 1} = 8 \cdot 4^2\) This is the correct one.
anonymous
  • anonymous
ok its c
anonymous
  • anonymous
128
anonymous
  • anonymous
yay I got 100 gtg
mathstudent55
  • mathstudent55
Yes, C is correct, 128.

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