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anonymous
 one year ago
the population of the earth is approximately 6.1 billion people and is growing at an annual rate of 1.4%. Assuming a Malthusian growth mode, find the world population in 29 years. Please round the answer to the nearest tenth of a billion.
anonymous
 one year ago
the population of the earth is approximately 6.1 billion people and is growing at an annual rate of 1.4%. Assuming a Malthusian growth mode, find the world population in 29 years. Please round the answer to the nearest tenth of a billion.

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perl
 one year ago
Best ResponseYou've already chosen the best response.1I think we can use this equation: $$ \Large y =6.1~\left(1 + \frac{1.4}{100} \right)^t $$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much for helping me :)

perl
 one year ago
Best ResponseYou've already chosen the best response.1the "malthusian model' seems a little ambiguous, but the two models come out about the same $$\Large y= 6.1 e ^{0.014 t } $$

perl
 one year ago
Best ResponseYou've already chosen the best response.1actually it does make a difference, since it says round to the tenth place using the equation with e, i get 9.2 billion rounded to nearest tenth place

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats what I got as well

perl
 one year ago
Best ResponseYou've already chosen the best response.1the two models come out differently, if you round out to the nearest tenth. i would go with the latter model, using e

perl
 one year ago
Best ResponseYou've already chosen the best response.1$$\Large { f(t) =6.1~\left(1 + .014 \right)^{~t} \\\Large f(29) =6.1~\left(1 + .014 \right)^{~29} = 9.12915 \\~\\\Large g(t)= 6.1 e ^{0.014 t } \\ g(29) = 6.1 e ^{0.014 \times 29 } = 9.154895 }$$
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