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yadu123

  • one year ago

In Paul Hewitt's book, he poses this question: "If the forces that act on a bullet and the recoiling gun from which it is fired are equal in magnitude, why do the bullet and gun have very different accelerations?" Think about Newton's Second Law (F = ma) and answer his question.

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  1. yadu123
    • one year ago
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    i know the mass of the bullet is less than the gun an that affects it but i dont know how

  2. IrishBoy123
    • one year ago
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    \(F = m_{bullet} \times a_{bullet} = m_{gun} \times a_{gun}\). If \(m_{gun} > m_{bullet}, \ then ..... \)????

  3. yadu123
    • one year ago
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    the force remains constant

  4. yadu123
    • one year ago
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    ok i get it

  5. yadu123
    • one year ago
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    gotta go

  6. IrishBoy123
    • one year ago
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    not really it's Newton's first law. to every action there is an equal an opposite reaction so just as the gun propels the bullet towards its target, the bullet pushes back on the gun - creating "the recoil", as it is called but because the bullet is much lighter, it goes off like billy-o, whereas the gun just recoils a bit in the hands of its holder.

  7. yadu123
    • one year ago
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    oh ok

  8. IrishBoy123
    • one year ago
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    sorry, Newton's **Third** Law ;p action and reaction.

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