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anonymous
 one year ago
Water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air?
0°, 90°, 37° , or 49°
? :/
anonymous
 one year ago
Water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0°, 90°, 37° , or 49° ? :/

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I remember that the critical angle is given by the subsequent formula: \[\Large \sin \left( {{\theta _c}} \right) = \frac{1}{n} = \frac{1}{{1.33}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! so that gets 0.751879 right? what happens next?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2we have to compute this value: \[\Large \arcsin \left( {0.7518} \right) = ...\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, it is: 48.753

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh :/ oops :P okay! so that means our solution is 49º?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! that's right!
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