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Babynini
 one year ago
Projecting Vertex.
Babynini
 one year ago
Projecting Vertex.

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acxbox22
 one year ago
Best ResponseYou've already chosen the best response.0sorry i dont know this stuff :(

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4\(proj_{\vec{v}}\vec{u} = \frac{\vec{v} \bullet \vec{u}}{\vec v^2}\vec{v}\) is the *vector* projection of \(\vec u \) on \(\vec v \). it's just a formula so calculate the various parts, eg \(\vec{v} \bullet \vec{u} = <11,3> \bullet <6,4>\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4\( \vec v ^2 = \vec v \bullet \vec v\)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1simplified u*v=78 v*v=52 is it right so far?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1Post your question on a new feed and i'll try :)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4"u • v = <66,12>" nah u • v = <11,3).<6,4> = (11)(6) + (3)(4) = 66  12 =  78

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1yep yep that's what I got for that one :)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4\(\vec u \bullet \vec v = <u_x,u_y> \bullet <v_x,v_y> = (u_x \times v_x) + (u_y \times v_y) \)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4sorry, bandwith issues, i am clearly behind times. let me read the thread again

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4v.v = <6,4><6,4> = 36 + 16 = 52 seems we agree

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1plug it into the formula?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1so we have \[\frac{ 78 }{ 52}v\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1woah where did you get<9,6> ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4v = <6,4> and, 78/52 = 3/2 and, 3/2 * <6,4> = <9,6> agree?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1so, is that the final answer then? o.0

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1or ..is that just what \[u _{1} \] equals?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4that answers (a). for (b) you have to .....!!! do something v similar

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1we would use (75/52)v again, yeah?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4you've already done \(\vec u_1\) that's what you just calculated so you need to do the same on \(\vec u_2\) so what is \(\vec u_2\) ? it is orthogonal to \(\vec v\) ...

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4<6,4>•<x,y> = 0 6x4y = 0 try: <6,4>•<4,6> or <6,4>•<4,6> both work we can use either

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1does what I did work? o.o

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1I'm pretty sure that's what the prof did in class but ah well haha

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4let me actually do it

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1thanks for taking the time to calculate it all :)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1so we have \[u _{1}=<9,6> u _{2}=<2,3>\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1what goes into \[proj _{v}u\]?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.1nevermind, they just wanted <9,6> there too :) thanks!!
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