anonymous
  • anonymous
The refractive index of cooking oil is 1.47, and the refractive index of water is 1.33. A thick layer of cooking oil is floating on top of water in a beaker. What is the critical angle for light passing from the oil into the water? 25º, 43º , 49º , or 65º ?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
we have to apply the law of Snell, so we can write: \[\Large {n_{OIL}}\sin {\theta _{OIL}} = {n_{WATER}} \cdot 1\]
anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
so: \[\Large \sin {\theta _{OIL}} = \frac{{{n_{WATER}}}}{{{n_{OIL}}}} = \frac{{1.33}}{{1.47}}\]

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anonymous
  • anonymous
0.90476 ?
Michele_Laino
  • Michele_Laino
and what is: arcsin(0.90476)=...?
anonymous
  • anonymous
0.0157916973 ?
Michele_Laino
  • Michele_Laino
no, it is : 64.791
anonymous
  • anonymous
oh sorry.. it is 64.79 ?
anonymous
  • anonymous
so our solution is 65º? sorry i was in the wrong mode on my calc :O
Michele_Laino
  • Michele_Laino
that's right! make sure to set "DEG" not "RAD" on your calculator
anonymous
  • anonymous
yay! thank you:)
Michele_Laino
  • Michele_Laino
:)

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