anonymous
  • anonymous
How do I evaluate sin 360 degrees?
Algebra
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anonymous
  • anonymous
How do I evaluate sin 360 degrees?
Algebra
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
do you know where 360 degrees is on the unit circle?
anonymous
  • anonymous
to the right
anonymous
  • anonymous
|dw:1433195551165:dw|

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anonymous
  • anonymous
so in numerical form, what would that be?
anonymous
  • anonymous
that was what my goal was
anonymous
  • anonymous
find the coordinates of that point the first one is cosine, the second one is sine here is a nice cheat sheet to help
anonymous
  • anonymous
1?
anonymous
  • anonymous
I do have options, they are: 0, 0.5, 1, and -0.5
anonymous
  • anonymous
0 doesnt fit I don't think
anonymous
  • anonymous
@satellite73 confirmation if i'm right or wrong? :(
anonymous
  • anonymous
the coordinates of that point are \((1,0)\) right?
anonymous
  • anonymous
i have no idea what "0 doesn't fit" means the second coordinate is 0, so \[\sin(360^\circ)=0\]

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