anonymous
  • anonymous
A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Michele_Laino
  • Michele_Laino
it is simple the toatl resistance is: R=20+10=30 Ohm so the requested current is: I= V/R= 9/30=...Amperes
Michele_Laino
  • Michele_Laino
total*
anonymous
  • anonymous
The answer choices are 0.38 A 0.75 A 1.35 A 6.00 A So do I go with 0.38 A

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Michele_Laino
  • Michele_Laino
sorry I have made an error
Michele_Laino
  • Michele_Laino
the total resistance is: \[\Large R = \frac{1}{{\frac{1}{{10}} + \frac{1}{{20}}}} = ...Ohms\]
Michele_Laino
  • Michele_Laino
what is R?
Michele_Laino
  • Michele_Laino
hint: R=6.67 Ohms so the requested current, is: I=V/R= 9/6.67=...Amperes
anonymous
  • anonymous
I got that answer but it doesn't match any answer choice.
Michele_Laino
  • Michele_Laino
what is your answer?
anonymous
  • anonymous
oh I messed up I forgot to divide 9/6.67 I am so dumb the answer is 1.35A
Michele_Laino
  • Michele_Laino
the answer is 1.35 Amperes, good job!
anonymous
  • anonymous
Thank you for your help. I should have been able to do this on my own. I just missed a tiny detail when I was trying to solve it myself.
Michele_Laino
  • Michele_Laino
thanks! :)

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