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anonymous

  • one year ago

A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit?

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  1. Michele_Laino
    • one year ago
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    it is simple the toatl resistance is: R=20+10=30 Ohm so the requested current is: I= V/R= 9/30=...Amperes

  2. Michele_Laino
    • one year ago
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    total*

  3. anonymous
    • one year ago
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    The answer choices are 0.38 A 0.75 A 1.35 A 6.00 A So do I go with 0.38 A

  4. Michele_Laino
    • one year ago
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    sorry I have made an error

  5. Michele_Laino
    • one year ago
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    the total resistance is: \[\Large R = \frac{1}{{\frac{1}{{10}} + \frac{1}{{20}}}} = ...Ohms\]

  6. Michele_Laino
    • one year ago
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    what is R?

  7. Michele_Laino
    • one year ago
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    hint: R=6.67 Ohms so the requested current, is: I=V/R= 9/6.67=...Amperes

  8. anonymous
    • one year ago
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    I got that answer but it doesn't match any answer choice.

  9. Michele_Laino
    • one year ago
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    what is your answer?

  10. anonymous
    • one year ago
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    oh I messed up I forgot to divide 9/6.67 I am so dumb the answer is 1.35A

  11. Michele_Laino
    • one year ago
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    the answer is 1.35 Amperes, good job!

  12. anonymous
    • one year ago
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    Thank you for your help. I should have been able to do this on my own. I just missed a tiny detail when I was trying to solve it myself.

  13. Michele_Laino
    • one year ago
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    thanks! :)

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