## anonymous one year ago A 10.0 Ω resistor is in parallel with a 20.0 Ω resistor and supplied by a 9.00 V battery. What is the total current passing through the circuit?

1. Michele_Laino

it is simple the toatl resistance is: R=20+10=30 Ohm so the requested current is: I= V/R= 9/30=...Amperes

2. Michele_Laino

total*

3. anonymous

The answer choices are 0.38 A 0.75 A 1.35 A 6.00 A So do I go with 0.38 A

4. Michele_Laino

sorry I have made an error

5. Michele_Laino

the total resistance is: $\Large R = \frac{1}{{\frac{1}{{10}} + \frac{1}{{20}}}} = ...Ohms$

6. Michele_Laino

what is R?

7. Michele_Laino

hint: R=6.67 Ohms so the requested current, is: I=V/R= 9/6.67=...Amperes

8. anonymous

9. Michele_Laino

10. anonymous

oh I messed up I forgot to divide 9/6.67 I am so dumb the answer is 1.35A

11. Michele_Laino

the answer is 1.35 Amperes, good job!

12. anonymous

Thank you for your help. I should have been able to do this on my own. I just missed a tiny detail when I was trying to solve it myself.

13. Michele_Laino

thanks! :)