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anonymous

  • one year ago

A certain (fictional) element has exactly three stable isotopes which occur in different proportions in nature. Two of the masses are given in the table below. Isotope Mass (u) Abundance (%) A 93.9896 52.0 B 95.9981 16.0 C ? ? The atomic weight of the element has been calculated as 93.644. Please find the mass and abundance of isotope C

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  1. anonymous
    • one year ago
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    93.9896(52/100)+95.9981(16/100)+c(32/100)=93.644 I believe you can understand it. :)

  2. anonymous
    • one year ago
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    @lelia_tan Thank you, if I may ask, why did you divide them by 100?

  3. aaronq
    • one year ago
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    to convert the percentages to numbers. 10% = \(\dfrac{10\%}{100\%}=0.1\)

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