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BloomLocke367
 one year ago
Find the area.
BloomLocke367
 one year ago
Find the area.

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BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433197250937:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay this link will help https://www.mathsisfun.com/algebra/trigareatrianglewithoutrightangle.html

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0http://prntscr.com/7c1xmi you need to find 3rd side of triangle it's not a right triangle so law of cosine ?familiar with this method ?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0kind of, I sort of know what it is, but I don't really know how to use it

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I have to eat dinner, be back in a sec

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I'm back, I wasn't that hungry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0ahh alright so did you eat candy ? :P

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0no, I had like a few bites.. I think it's my nerves that have me not hungry.. I'm very stressed.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm c^2 = a^2 +b^2 2abcos C\] dw:1433199653612:dw plug in value solve for c

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0wait, don't I need to use law of sines for this?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0mhm nope bec given is two sides and one angle

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0yes, you use cosine if you have 3 sides, and law of sines if you have 2 sides and an angle.. I'm almost positive

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0http://mathforum.org/library/drmath/view/69918.html you can use law of cosines to find 3rd side

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0but... https://www.mathsisfun.com/algebra/trigsinelaw.html ...

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0oh, okay.. sorry for doubting you

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0nah it's fine! i like it :P

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0c^2=64+3242(8)(18)cos(25), so far, right?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0c^2=388288cos(25) c^2=100cos(25)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I got c^2=90.63 so c=9.52

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0how? (sorry, I had to go to bed) @Nnesha

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Why do we need to find value of c? dw:1433254516249:dw Obviously, \(\large A_{\text{triangle}} = \dfrac12bh\) We already have base \(\overline{\text{QR}} = 8\) So we need to find h: Using fact that \(\sin\theta = \dfrac{\text{Opp}}{\text{Hyp}}\), we have \(\sin Q = \dfrac{h}{\overline{\text{PQ}}} = \dfrac{h}{18}\) Yield \(18\sin(25^\text o) = h\) So we have \(A_{\text{triangle}} = \dfrac12~\overline{\text{QR}}~h = \dfrac{1}{2}(8)(18\sin(25^\text o)~) = \cdots~?\)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Me too. So that's your area.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Do you understand what I wrote?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0oh, okay. kinda, I don't understand how you got the height, but the rest I get.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1well, we can set up height of triangle here:

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0okay. Can you help with more?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433254921641:dw Then we can treat it as "new triangle" dw:1433254928278:dw From here, we have hypotenuse and angle Q and height. So using sine, we can solve for h. Then we use that height to solve for area of original triangle.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhhhh okay. and it's the same height for both triangles?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Same angle and hypotenuse, so yeah same height,

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0alright. I have some more questions, if that's okay. I'll post a new question and tag you
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