anonymous
  • anonymous
A current of 3.20 A in a solenoid produces a magnetic field of 4.0 × 10^-3 T. The current is changed to 6.40 A. What is the magnitude of the magnetic field after the change?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
Thank you for coming to help me again
IrishBoy123
  • IrishBoy123
for a solenoid, magnetic field strength \(B = \mu n I\) = permeability \( \mu \times\) turn density \(n \times\) current \(I\). all you have done is double the current, so the magnetic field, B, should also do what?

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anonymous
  • anonymous
16 × 10^-3 T 8.0 × 10^-3 T <----- would this be the answer? 2.0 × 10^-3 T 1.0 × 10^-3 T
IrishBoy123
  • IrishBoy123
yay!!

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