A current of 3.20 A in a solenoid produces a magnetic field of 4.0 × 10^-3 T. The current is changed to 6.40 A. What is the magnitude of the magnetic field after the change?

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A current of 3.20 A in a solenoid produces a magnetic field of 4.0 × 10^-3 T. The current is changed to 6.40 A. What is the magnitude of the magnetic field after the change?

Physics
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Thank you for coming to help me again
for a solenoid, magnetic field strength \(B = \mu n I\) = permeability \( \mu \times\) turn density \(n \times\) current \(I\). all you have done is double the current, so the magnetic field, B, should also do what?

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Other answers:

16 × 10^-3 T 8.0 × 10^-3 T <----- would this be the answer? 2.0 × 10^-3 T 1.0 × 10^-3 T
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