## anonymous one year ago A current of 3.20 A in a solenoid produces a magnetic field of 4.0 × 10^-3 T. The current is changed to 6.40 A. What is the magnitude of the magnetic field after the change?

1. anonymous

2. anonymous

Thank you for coming to help me again

3. IrishBoy123

for a solenoid, magnetic field strength $$B = \mu n I$$ = permeability $$\mu \times$$ turn density $$n \times$$ current $$I$$. all you have done is double the current, so the magnetic field, B, should also do what?

4. anonymous

16 × 10^-3 T 8.0 × 10^-3 T <----- would this be the answer? 2.0 × 10^-3 T 1.0 × 10^-3 T

5. IrishBoy123

yay!!