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anonymous
 one year ago
Proportionality Theorem
I have the first column of the proof I just need help with the second.
anonymous
 one year ago
Proportionality Theorem I have the first column of the proof I just need help with the second.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first two are most likely incorrect

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1why do you think the first two are incorrect?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am over all unsure about proofs. I am horrible when it comes to them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0guess I was right :p

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1right in that the first two lines of the 2 column proof are incorrect? Or that they are correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They are correct. :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 down 4 more lines to figure out ..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1why is angle ABC congruent to angle ADE ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont know. because they're congruent angles?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1That's circular reasoning and flawed. You cannot make a statement and then back up that statement with the same statement.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1see this page https://www.mathsisfun.com/geometry/parallellines.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ugh. I hate proofs. Does it have to do with Bisectors?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1go ahead and look through the link I posted be sure to play with the interactive applet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They're corresponding angles?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433203991985:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433204002334:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what about the next line?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one sec lemme fill in the third

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alrighty. give me a second to look on that link

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this one confuses me.. possibly consecutive interior angles?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres angles in and outside.. kind of.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433204262730:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1we are given that DE  BC dw:1433204337699:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1and as you pointed out \[\Large \sphericalangle ABC \cong \sphericalangle ADE\] because they are corresponding angles dw:1433204439413:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1The same applies for angle ACB and angle AED \[\Large \sphericalangle ACB \cong \sphericalangle AED\] because they are corresponding angles dw:1433204518237:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0soo corresponding angles again?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now the 5th line to me makes no sense its like a triangle then a segment

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i see what you mean. oops. aha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Intersecting Chords Theorem?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1http://www.regentsprep.org/regents/math/geometry/gp11/LsimilarProof.htm

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1keep in mind that the 2 column proof builds up to what we want to aim for. Each step/line is necessary in getting to where we want to go

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yep, Angle Angle dw:1433205268084:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433205298484:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so we have a pair of congruent corresponding angles, therefore that's why \(\large \triangle ABC \sim \triangle DBA\) is true (because of the AA similarity theorem)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see what you mean.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then what about the last one?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1any thoughts on it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean. I see how they relate. corresponding sides?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1how can we use line 5 to lead up to line 6 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Honestly I have no idea.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1if you look through these theorems http://www.regentsprep.org/regents/math/geometry/gp11/LsimilarProof.htm which theorem deals with proportions?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes specifically the converse of the SSS similarity theorem

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the SSS similarity theorem if the sides are all in proportion (as shown in the fractions), then the triangles are similar

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1converse of the SSS similarity theorem if the triangles are similar, then the sides form a proportion

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the converse is the "backwards" version of the original, so to speak

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see. so does this look good?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's not just SSS theorem, it's the converse of that theorem

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1everything else looks good though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so write converse sss theorem?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah or something like that so the teacher knows

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0BTW this isn't a test or quiz or anything.. I see alot of students ask for answers on here.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ok I hope that it's not. Those sorts of things should be taken individually without any help. If anything, they should be proctored.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways Thank you for the help!! It means the world!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome
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