Can someone please help me solve this matrix equation??? Will medal, fan and give a testimony!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Can someone please help me solve this matrix equation??? Will medal, fan and give a testimony!

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
I have to solve for x, y and z but I'm not sure how. I was told to use this equation so I already made A the inverse, but I'm not sure what to do next...\[A^-1\times B \]
where is your A^-1 matrix? can you draw it on here? It seems that after we find the inverse we're supposed to use matrix multiplication

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I already made the inverse, this is what it originally looked like before I took the inverse
1 Attachment
ok so then we need to use matrix multiplication . your A^-1 matrix is a 3 x 3 matrix and your B is a 3 x 1 matrix so your A^-1 x B should be a 3 x 1 matrix.
oh ok
I'm not sure how to do that multiplication...
Is this going to solve x y and z?
only because we have an m x n matrix and a n x p matrix . They share the same dimension size in the middle so the end result is m x p 3 x 3 A^-1 3 x 1 B 3 x 3 3 x 1 3 x 1 should be your end result... but I don't think it's going to lead farther enough to solve the equation because after you do matrix multiplication that new matrix will be to be written down x y z = 4 4x 4y 0 z = 3 0x+y-3z = -10 then since you have an augmented matrix of A l B 1 1 1 l 4 4 4 0 l 3 0 1 -3 l -10 then we use row operations.
we need the terms below the main diagonal 0 with row operations that should be easy, but you really need is a reduced row echelon matrix. which means the terms above the diagonal have to go to 0 too... the operations apply to the entire row
whoa I'm lost...
I lost it right after you said 'then since you have an augmented matrix of A l B '
do you know row operations for a matrix? Like how to make it echelon form or reduce row echelon form?
oh you know I found it on a site where it explains it step by step but thank you SO much for helping me
ok ^^
I think you can just take matrix multiplication on the left side of the original matrix and then use row operations... then you will find x y z but the numbers are going to be bigger while you're doing row operations. so when you have a format like 1 0 0 l 3 0 1 0 l 5 0 0 1 l 5 that means x = 3, y =5, and z=5 (just an example) if you plug those values back into the original equation you will know if the entire left matrix = the right matrix a.k.a A =B. I had a hard time with these when I first started but when I practiced and learned the rules, it became easy afterwards.

Not the answer you are looking for?

Search for more explanations.

Ask your own question