Proofs..

- anonymous

Proofs..

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- schrodinger

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- anonymous

@jim_thompson5910 mind helping with one more? :/

- jim_thompson5910

what's your question?

- anonymous

oops wrong one

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## More answers

- anonymous

##### 1 Attachment

- jim_thompson5910

what's the reasoning for line 2? any idea?

- anonymous

No. I mean they are talking about one angle being equal to itself..

- jim_thompson5910

which property makes that true?

- anonymous

Angle of a triangle? :l I'm clueless

- jim_thompson5910

when you look into a mirror, you see your ______

- anonymous

REFLECTION

- anonymous

This is why I like your help. you make in understandable.

- jim_thompson5910

yep REFLEction
so the REFLExive property is why A = A is true. it's trivial and seems kinda stupid (of course something is equal to itself, how could it not?) but at the same time it's good to have a rigorous set of rules

- jim_thompson5910

see the first line
http://www.regentsprep.org/regents/math/geometry/gpb/theorems.htm

- anonymous

I feel like you have a folder of math websites. You have so many helpful ones o.o

- jim_thompson5910

sometimes, but others I google

- jim_thompson5910

and regents prep tends to pop up a lot (esp with geometry)

- anonymous

ahh.

- anonymous

So what about the last line?

- anonymous

Corresponding sides?

- jim_thompson5910

I'm checking your line 3 and line 4

- anonymous

alright

- jim_thompson5910

from this link we visited earlier
http://www.regentsprep.org/regents/math/geometry/gp11/LsimilarProof.htm
I'm going to focus on the SAS similarity theorem. See attached

##### 1 Attachment

- jim_thompson5910

That theorem says if you have a pair of corresponding congruent angles, and you have that proportion mentioned in the attachment, then the triangles are similar

- anonymous

okay

- anonymous

was one of the lines wrong or are we on the last line?

- jim_thompson5910

so that's the reason for line 3.

- jim_thompson5910

we only use the AA theorem IF we had 2 congruent corresponding angles. We had that last time, but we don't have that this time

- anonymous

oh..

- anonymous

so would it be sas?

- jim_thompson5910

SAS similarity theorem, yes

- anonymous

is the fourth line okay?

- jim_thompson5910

no, but luckily you might know the theorem

- jim_thompson5910

you mentioned the AA theorem. What exactly does the AA theorem say?

- anonymous

AA? xD

- anonymous

Angle Angle

- jim_thompson5910

specifically what does the entire theorem say? (other than just Angle Angle)

- anonymous

To show two triangles are similar, it is sufficient to show that two angles of one triangle are congruent (equal) to two angles of the other triangle.
Theorem:
If two angles of one triangle are congruent to two angles of another triangle, the triangles are similar.

- jim_thompson5910

So
IF the angles are congruent
THEN the triangles are similar
flip that around to say...
IF the triangles are similar
THEN the angles are congruent

- jim_thompson5910

the theorem you wrote out is the original AA similarity theorem
the flipped version is the converse of that said theorem

- anonymous

Alright.. so would it be a converse
AA theorem?

- jim_thompson5910

converse of the AA similarity theorem, yep

- anonymous

And then the last line

- jim_thompson5910

any ideas?

- anonymous

Parallel lines?

- jim_thompson5910

well that's what you want to prove

- jim_thompson5910

how can you use the previous line?

- jim_thompson5910

https://www.mathsisfun.com/geometry/parallel-lines.html

- anonymous

I dont understand how to use the line before

- anonymous

Traversal something?

- jim_thompson5910

this might be of better help
http://www.nhvweb.net/nhhs/math/mschuetz/files/2012/11/Section-3-3-2012-2013.pdf

- anonymous

Which one :/

- jim_thompson5910

first page

- anonymous

Corresponding angles?

- jim_thompson5910

the converse of the corresponding angles theorem

- anonymous

Once again thank you!

- jim_thompson5910

np

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