Proofs..

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@jim_thompson5910 mind helping with one more? :/
what's your question?
oops wrong one

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Other answers:

1 Attachment
what's the reasoning for line 2? any idea?
No. I mean they are talking about one angle being equal to itself..
which property makes that true?
Angle of a triangle? :l I'm clueless
when you look into a mirror, you see your ______
REFLECTION
This is why I like your help. you make in understandable.
yep REFLEction so the REFLExive property is why A = A is true. it's trivial and seems kinda stupid (of course something is equal to itself, how could it not?) but at the same time it's good to have a rigorous set of rules
see the first line http://www.regentsprep.org/regents/math/geometry/gpb/theorems.htm
I feel like you have a folder of math websites. You have so many helpful ones o.o
sometimes, but others I google
and regents prep tends to pop up a lot (esp with geometry)
ahh.
So what about the last line?
Corresponding sides?
I'm checking your line 3 and line 4
alright
from this link we visited earlier http://www.regentsprep.org/regents/math/geometry/gp11/LsimilarProof.htm I'm going to focus on the SAS similarity theorem. See attached
1 Attachment
That theorem says if you have a pair of corresponding congruent angles, and you have that proportion mentioned in the attachment, then the triangles are similar
okay
was one of the lines wrong or are we on the last line?
so that's the reason for line 3.
we only use the AA theorem IF we had 2 congruent corresponding angles. We had that last time, but we don't have that this time
oh..
so would it be sas?
SAS similarity theorem, yes
is the fourth line okay?
no, but luckily you might know the theorem
you mentioned the AA theorem. What exactly does the AA theorem say?
AA? xD
Angle Angle
specifically what does the entire theorem say? (other than just Angle Angle)
To show two triangles are similar, it is sufficient to show that two angles of one triangle are congruent (equal) to two angles of the other triangle. Theorem: If two angles of one triangle are congruent to two angles of another triangle, the triangles are similar.
So IF the angles are congruent THEN the triangles are similar flip that around to say... IF the triangles are similar THEN the angles are congruent
the theorem you wrote out is the original AA similarity theorem the flipped version is the converse of that said theorem
Alright.. so would it be a converse AA theorem?
converse of the AA similarity theorem, yep
And then the last line
any ideas?
Parallel lines?
well that's what you want to prove
how can you use the previous line?
https://www.mathsisfun.com/geometry/parallel-lines.html
I dont understand how to use the line before
Traversal something?
this might be of better help http://www.nhvweb.net/nhhs/math/mschuetz/files/2012/11/Section-3-3-2012-2013.pdf
Which one :/
first page
Corresponding angles?
the converse of the corresponding angles theorem
Once again thank you!
np

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