anonymous
  • anonymous
Can someone look at this and tell me what I did wrong to get this answer??? Will medal!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
This took me so long to do I'm so upset... I was so proud of myself until I got that answer :(
UsukiDoll
  • UsukiDoll
why does the formula require the inverse? Wait I see what the problem is. You don't have to include x y z you just include the numbers that are attached to the x y z in the set of linear equation s

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anonymous
  • anonymous
um, explain?
anonymous
  • anonymous
someone told me that the formula was A^-1*B...
anonymous
  • anonymous
and when I looked it up that was correct, using the inverse
amistre64
  • amistre64
inverses are such a pain, when they get big its sometimes more efficient to use augmented form.
UsukiDoll
  • UsukiDoll
I think something happened to your calculations.. your x is huge
UsukiDoll
  • UsukiDoll
that's what I was trying to say... put it in an augmented matrix format and use row operations...
anonymous
  • anonymous
I don't remember learning that I don't understand!
amistre64
  • amistre64
rref{ {1,1,1,4}, {4,5,0,3}, {0,1,-3,-10} } http://www.wolframalpha.com/input/?i=rref%7B+%7B1%2C1%2C1%2C4%7D%2C+%7B4%2C5%2C0%2C3%7D%2C+%7B0%2C1%2C-3%2C-10%7D+%7D
amistre64
  • amistre64
less room for error in my opinion
UsukiDoll
  • UsukiDoll
do you see the original system of equations? YOu just put the numbers from the systems of equations like this 1 1 1 l 4 4 5 0 l 3 0 1 -3 l -10 and use row operations... you don't have a 0 in the main diagonal so row swapping isn't required.
anonymous
  • anonymous
just tell me what I did wrong so I can fix it and move on! I've been working on this problem for HOURS
anonymous
  • anonymous
lol math making people crazy when ever they can't find the answer ;D
anonymous
  • anonymous
I don't understand :'(
anonymous
  • anonymous
nothing nothing they are going help :D
amistre64
  • amistre64
your inverse has one bad spot ... row1 col3: should be -5
anonymous
  • anonymous
I used a calculator to find the inverse.... it shouldn't be wrong..... but I'll double check
UsukiDoll
  • UsukiDoll
I would've used augmented version and use row operations..
amistre64
  • amistre64
it prolly had a negative, and you might have missed it ... but thats the trouble spot
anonymous
  • anonymous
oh... you're right @amistre64 I wrote it wrong...
UsukiDoll
  • UsukiDoll
I've made plenty of mistakes on my exams xD! It's not a problem. xD
anonymous
  • anonymous
thank you so much... @amistre64 I'll calculate it now and look at my answer to see if its correct this time
amistre64
  • amistre64
-50 instead of +50, so your 100 off on the first row :) 100-98 = 2
amistre64
  • amistre64
good effort
anonymous
  • anonymous
haha thanks I'm not sure who to give the medal to... :P
anonymous
  • anonymous
@amistre64 can you give @UsukiDoll a medal for me since I medaled you?
UsukiDoll
  • UsukiDoll
interesting.. so there is more than one method to solve this... my professor didn't even teach the inverse version... just told me to put it in augmented matrix form and row operations solve away until I have reduce row echelon form. So the final matrix wouldv'e looked like this 1 0 0 l 2 0 1 0 l-1 0 0 1 l 3 for x =2, y = -1, z=3
anonymous
  • anonymous
Much better :D
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UsukiDoll
  • UsukiDoll
yay :)

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