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anonymous

  • one year ago

PLEASE HELP! WILL MEDAL! Find the sum of the series.

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  1. anonymous
    • one year ago
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    \[\sum_{n=1}^{15} (2n+1)\]

  2. anonymous
    • one year ago
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    there are a couple ways to do this

  3. anonymous
    • one year ago
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    Okay I need the simplest way because I'm not good with this.

  4. anonymous
    • one year ago
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    ok lets find the first term, which means replace \(n\) by \(1\) what do you get?

  5. anonymous
    • one year ago
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    3?

  6. anonymous
    • one year ago
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    if that is confusing too, let me know and i will show you lol no not "3?" just "3"

  7. anonymous
    • one year ago
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    I know it is just 3 I was asking if 3 was right.

  8. anonymous
    • one year ago
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    yeah \(2\times 1+1=3\) ok now the top number is 15 so lets find the 15th term replace \(n\) by \(15\) and see what you get

  9. anonymous
    • one year ago
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    31

  10. anonymous
    • one year ago
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    ok good now there are 15 terms all together one formula you can use is \[\huge \frac{n}{2}\left(a_1+a_n\right )\]

  11. anonymous
    • one year ago
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    you computed \(a_1=3,a_{15}=31\) and in this case \(n=15\)

  12. anonymous
    • one year ago
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    so do this \[\frac{15}{2}(3+31)\]

  13. anonymous
    • one year ago
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    15/2(33)

  14. anonymous
    • one year ago
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    add first, divide by 2 then multiply by 15

  15. anonymous
    • one year ago
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    you got that?

  16. anonymous
    • one year ago
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    I meant 34 my number buttons are acting up and no. I was just stating the equation.

  17. anonymous
    • one year ago
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    ok so now divide 34 by 2 then multiply the result by 15

  18. anonymous
    • one year ago
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    255

  19. anonymous
    • one year ago
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    you found the sount

  20. anonymous
    • one year ago
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    sound bingo yes good work

  21. anonymous
    • one year ago
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    Thank you for your help!

  22. anonymous
    • one year ago
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    yw

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