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anonymous

  • one year ago

Just need someone to check my answer. One problem only. 3. A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show your work. (µC = 1.0 × 10–6 C) The potential difference * charge = potential energy change of charge delta V = 10J/(5*10^-6) = 2*10^6 volts

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  1. anonymous
    • one year ago
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    @Thesmarterone help?

  2. anonymous
    • one year ago
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    you have the formula on it \(\triangle U= \dfrac{1}{2}CV^2\) so that you can calculate the V from it, just plug in the numbers. Don't forget convert the unit.

  3. anonymous
    • one year ago
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    oh ok thnx @Thesmarterone can i tag you for physics questions in the future?

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