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anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = 2.
anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = 2.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol no one likes these conic section problems, do they?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but it is real real easy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you now what the parabola looks like? if so, we can do it in like 15 seconds

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0open up, down, left or right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433210682010:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not so sure now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and the vertex is exactly half way between the focus and the directrix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it is evidently at \((0,0)\) making your equation look like \[4py=x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all you need is \(p\) which is the distance between the focus and the vertex (or the vertex and the directrix) which is clearly 2 final answer \[8y=x^2\]
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