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anonymous

  • one year ago

Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.

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  1. anonymous
    • one year ago
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    lol no one likes these conic section problems, do they?

  2. anonymous
    • one year ago
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    but it is real real easy

  3. anonymous
    • one year ago
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    do you now what the parabola looks like? if so, we can do it in like 15 seconds

  4. anonymous
    • one year ago
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    Yes. I think so.

  5. anonymous
    • one year ago
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    open up, down, left or right?

  6. anonymous
    • one year ago
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    |dw:1433210682010:dw|

  7. anonymous
    • one year ago
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    Opens down?

  8. anonymous
    • one year ago
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    I'm not so sure now.

  9. anonymous
    • one year ago
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    yes it iopens down

  10. anonymous
    • one year ago
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    and the vertex is exactly half way between the focus and the directrix

  11. anonymous
    • one year ago
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    so it is evidently at \((0,0)\) making your equation look like \[4py=x^2\]

  12. anonymous
    • one year ago
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    all you need is \(p\) which is the distance between the focus and the vertex (or the vertex and the directrix) which is clearly 2 final answer \[-8y=x^2\]

  13. anonymous
    • one year ago
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    Thanks!

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