anonymous
  • anonymous
Find the standard form of the equation of the parabola with a focus at (0, -2) and a directrix at y = 2.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
lol no one likes these conic section problems, do they?
anonymous
  • anonymous
but it is real real easy
anonymous
  • anonymous
do you now what the parabola looks like? if so, we can do it in like 15 seconds

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anonymous
  • anonymous
Yes. I think so.
anonymous
  • anonymous
open up, down, left or right?
anonymous
  • anonymous
|dw:1433210682010:dw|
anonymous
  • anonymous
Opens down?
anonymous
  • anonymous
I'm not so sure now.
anonymous
  • anonymous
yes it iopens down
anonymous
  • anonymous
and the vertex is exactly half way between the focus and the directrix
anonymous
  • anonymous
so it is evidently at \((0,0)\) making your equation look like \[4py=x^2\]
anonymous
  • anonymous
all you need is \(p\) which is the distance between the focus and the vertex (or the vertex and the directrix) which is clearly 2 final answer \[-8y=x^2\]
anonymous
  • anonymous
Thanks!

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