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you need the pythagorean theorem a^2+b^2 =c^2 so for tan x = 3/4 that's tan x = opposite /|dw:1433209669615:dw| adjacent
so we need to solve for c 3^2+4^2 =c^2 9+16 =c^2 25=c^2 5 = c normally the answer would be 5 and -5 , but we can't have negative signs at all for geometric shapes.
Imma eat lunch
UsukiDoll The angle 'x' would be located in the lower left corner of the triangle.
sine (x) = opposite / hypotenuse sine (x) = 3 / c
So that would be 4/3??
No sine (x) = 3 / c What is 'c'?
it's asking for the sin x version we are given that tan x = 3/4 tan x is usually opposite/adjacent cos x is adjacent/hypotenuse sin x is opposite / hypotenuse your hypotenuse value is missing!
if the opposite -> 3 adjacent -> 4 our sin x is 3/ ? that ? is our unknown and we need the Pythagorean theorem for a^2+b^2=c^2
so using the Pythagorean theorem a^2+b^2=c^2 let your a = 3 and b = 4 3^2+(4)^2=c^2 9+16=c^2 25=c^2 5 = c that's your hypotenuse! since Hypotenuse is 5 and makes sense since it's supposed to be the longest side of the triangle Your sin x is opposite/ hypotenuse which is 3/5
sorry if I sounded a bit arrogant... but.. the reason why it's not 4/3 is because that's the cotangent so... sin x = opposite/hypotenuse cos x = adjacent/hypotenuse tan x = opposite/adjacent csc x, sec x, and cot x are backwards versions of what I've typed above tan x = opposite/adjacent (3/4) cot x = adjacent/opposite (4/3)