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If tanX=3/4 , what is sin X??
Stacey Warren - Expert brainly.com
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you need the pythagorean theorem a^2+b^2 =c^2
so for tan x = 3/4 that's tan x = opposite /|dw:1433209669615:dw| adjacent
so we need to solve for c
5 = c
normally the answer would be 5 and -5 , but we can't have negative signs at all for geometric shapes.
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The angle 'x' would be located in the lower left corner of the triangle.
sine (x) = opposite / hypotenuse
sine (x) = 3 / c
So that would be 4/3??
sine (x) = 3 / c
What is 'c'?
it's asking for the sin x version
we are given that tan x = 3/4
tan x is usually opposite/adjacent
cos x is adjacent/hypotenuse
sin x is opposite / hypotenuse
your hypotenuse value is missing!
if the opposite -> 3
adjacent -> 4
our sin x is 3/ ?
that ? is our unknown and we need the Pythagorean theorem for a^2+b^2=c^2
so using the Pythagorean theorem
let your a = 3 and b = 4
5 = c
that's your hypotenuse! since Hypotenuse is 5 and makes sense since it's supposed to be the longest side of the triangle
Your sin x is opposite/ hypotenuse which is 3/5
sorry if I sounded a bit arrogant... but.. the reason why it's not 4/3 is because that's the cotangent
sin x = opposite/hypotenuse
cos x = adjacent/hypotenuse
tan x = opposite/adjacent
csc x, sec x, and cot x are backwards versions of what I've typed above
tan x = opposite/adjacent (3/4)
cot x = adjacent/opposite (4/3)