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stuck-help

  • one year ago

simplified form of the expression in the comments

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  1. stuck-help
    • one year ago
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    \[\left( 3c ^{2}d ^{4} \right)^{3}x \left( 2c ^{5}d ^{8} \right)^{3}\]

  2. stuck-help
    • one year ago
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    i have no idea and need the work i have work this equation so many ways and cannot get the answer

  3. stuck-help
    • one year ago
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    @Babynini are you working this problem

  4. anonymous
    • one year ago
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    do u have ANY answer choices?

  5. anonymous
    • one year ago
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    multiply each exponent in the first expression by 3

  6. anonymous
    • one year ago
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    also in the second one

  7. stuck-help
    • one year ago
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    yes but i have to have the work i redoing the problems and have to the work

  8. stuck-help
    • one year ago
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    @satellite73 do i multiply the 3exponent on the out side of the () to the exponents on the inside or the other #s

  9. anonymous
    • one year ago
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    what does "have the work" mean? multiply is multiply the first term will become \[3^3c^6d^{12}\]

  10. anonymous
    • one year ago
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    don't forget to cube the three also

  11. stuck-help
    • one year ago
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    i have to write everything you do down

  12. anonymous
    • one year ago
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    in the second term, again multiply every exponent by 3 don't forget to cube the 2 as well

  13. anonymous
    • one year ago
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    then when you are done, add the exponents with the like bases

  14. stuck-help
    • one year ago
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    \[3^{3} +2^{3}\] add the 3 and 2 and the exponents 3 and 3

  15. Babynini
    • one year ago
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    (did yall figure this out? :) )

  16. anonymous
    • one year ago
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    \[3^3c^6d^{12}\times 2^3c^{15}d^{24}\] is a start

  17. anonymous
    • one year ago
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    now add up the exponents for the c and the d

  18. stuck-help
    • one year ago
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    i did it wrong hold on so i can fix it

  19. stuck-help
    • one year ago
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    \[5^{6}2c ^{21}2d ^{35}\]

  20. stuck-help
    • one year ago
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    is what i got @satellite73

  21. anonymous
    • one year ago
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    d³⁶ *

  22. stuck-help
    • one year ago
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    yes \[2d ^{36}\]

  23. anonymous
    • one year ago
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    24+12 = 36..

  24. anonymous
    • one year ago
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    yep

  25. stuck-help
    • one year ago
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    i just wrote it wrong pressed the wrong button

  26. stuck-help
    • one year ago
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    @satellite73 is that all because that doesnt match any of my answers

  27. anonymous
    • one year ago
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    \[c^{21}d^{34}\]and in front should be \[27\times 8\]

  28. stuck-help
    • one year ago
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    how ?

  29. stuck-help
    • one year ago
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    how do you get 27*8

  30. anonymous
    • one year ago
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    \[3^3=27,2^3=8\]

  31. stuck-help
    • one year ago
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    thank you @satellite73

  32. stuck-help
    • one year ago
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    i have the answer \[216 c ^{21} d ^{36}\]

  33. stuck-help
    • one year ago
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    can you help with one more ill open it in another

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