stuck-help
  • stuck-help
simplified form of the expression in the comments
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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stuck-help
  • stuck-help
\[\left( 3c ^{2}d ^{4} \right)^{3}x \left( 2c ^{5}d ^{8} \right)^{3}\]
stuck-help
  • stuck-help
i have no idea and need the work i have work this equation so many ways and cannot get the answer
stuck-help
  • stuck-help
@Babynini are you working this problem

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More answers

anonymous
  • anonymous
do u have ANY answer choices?
anonymous
  • anonymous
multiply each exponent in the first expression by 3
anonymous
  • anonymous
also in the second one
stuck-help
  • stuck-help
yes but i have to have the work i redoing the problems and have to the work
stuck-help
  • stuck-help
@satellite73 do i multiply the 3exponent on the out side of the () to the exponents on the inside or the other #s
anonymous
  • anonymous
what does "have the work" mean? multiply is multiply the first term will become \[3^3c^6d^{12}\]
anonymous
  • anonymous
don't forget to cube the three also
stuck-help
  • stuck-help
i have to write everything you do down
anonymous
  • anonymous
in the second term, again multiply every exponent by 3 don't forget to cube the 2 as well
anonymous
  • anonymous
then when you are done, add the exponents with the like bases
stuck-help
  • stuck-help
\[3^{3} +2^{3}\] add the 3 and 2 and the exponents 3 and 3
Babynini
  • Babynini
(did yall figure this out? :) )
anonymous
  • anonymous
\[3^3c^6d^{12}\times 2^3c^{15}d^{24}\] is a start
anonymous
  • anonymous
now add up the exponents for the c and the d
stuck-help
  • stuck-help
i did it wrong hold on so i can fix it
stuck-help
  • stuck-help
\[5^{6}2c ^{21}2d ^{35}\]
stuck-help
  • stuck-help
is what i got @satellite73
anonymous
  • anonymous
d³⁶ *
stuck-help
  • stuck-help
yes \[2d ^{36}\]
anonymous
  • anonymous
24+12 = 36..
anonymous
  • anonymous
yep
stuck-help
  • stuck-help
i just wrote it wrong pressed the wrong button
stuck-help
  • stuck-help
@satellite73 is that all because that doesnt match any of my answers
anonymous
  • anonymous
\[c^{21}d^{34}\]and in front should be \[27\times 8\]
stuck-help
  • stuck-help
how ?
stuck-help
  • stuck-help
how do you get 27*8
anonymous
  • anonymous
\[3^3=27,2^3=8\]
stuck-help
  • stuck-help
thank you @satellite73
stuck-help
  • stuck-help
i have the answer \[216 c ^{21} d ^{36}\]
stuck-help
  • stuck-help
can you help with one more ill open it in another

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