simplified form of the expression in the comments

- stuck-help

simplified form of the expression in the comments

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- stuck-help

\[\left( 3c ^{2}d ^{4} \right)^{3}x \left( 2c ^{5}d ^{8} \right)^{3}\]

- stuck-help

i have no idea and need the work i have work this equation so many ways and cannot get the answer

- stuck-help

@Babynini are you working this problem

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## More answers

- anonymous

do u have ANY answer choices?

- anonymous

multiply each exponent in the first expression by 3

- anonymous

also in the second one

- stuck-help

yes but i have to have the work i redoing the problems and have to the work

- stuck-help

@satellite73 do i multiply the 3exponent on the out side of the () to the exponents on the inside or the other #s

- anonymous

what does "have the work" mean? multiply is multiply
the first term will become
\[3^3c^6d^{12}\]

- anonymous

don't forget to cube the three also

- stuck-help

i have to write everything you do down

- anonymous

in the second term, again multiply every exponent by 3
don't forget to cube the 2 as well

- anonymous

then when you are done, add the exponents with the like bases

- stuck-help

\[3^{3} +2^{3}\]
add the 3 and 2 and the exponents 3 and 3

- Babynini

(did yall figure this out? :) )

- anonymous

\[3^3c^6d^{12}\times 2^3c^{15}d^{24}\] is a start

- anonymous

now add up the exponents for the c and the d

- stuck-help

i did it wrong hold on so i can fix it

- stuck-help

\[5^{6}2c ^{21}2d ^{35}\]

- stuck-help

is what i got @satellite73

- anonymous

d³⁶ *

- stuck-help

yes \[2d ^{36}\]

- anonymous

24+12 = 36..

- anonymous

yep

- stuck-help

i just wrote it wrong pressed the wrong button

- stuck-help

@satellite73 is that all because that doesnt match any of my answers

- anonymous

\[c^{21}d^{34}\]and in front should be
\[27\times 8\]

- stuck-help

how ?

- stuck-help

how do you get 27*8

- anonymous

\[3^3=27,2^3=8\]

- stuck-help

thank you @satellite73

- stuck-help

i have the answer \[216 c ^{21} d ^{36}\]

- stuck-help

can you help with one more ill open it in another

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