## anonymous one year ago THIS IS REALLY CONFUSING Choose the system of linear inequalities that represent the given scenario. Let a represent the number of adult tickets and let c represent the number of children tickets. There were up to 1,200 tickets available for the spring carnival. Adult tickets cost $6.00 and children’s tickets cost$3.50. How many tickets of each could be sold to make at least $6,450? A; https://media.education2020.com/evresources/2066753_answer_choice_a.png B; https://media.education2020.com/evresources/2066753_answer_choice_b.png C https://media.education2020.com/evresources/2066753_answe • This Question is Closed 1. anonymous 2. jim_thompson5910 a = # of adult tickets c = # of child tickets a+c represents all of the tickets sold because you can only choose one or the other since "There were up to 1,200 tickets available", this means $\Large a+c \le 1200$ the key word here is "up to" which means "maximum". The 1200 is the highest we can go in terms of total number of tickets 3. jim_thompson5910 "Adult tickets cost$6.00 and children’s tickets cost $3.50." 'a' adult tickets are sold, so they rake in 6a dollars c child tickets are sold, they rake in 3.5c dollars in total, the combined total is 6a+3.5c dollars we want to "make at least$6,450", which means we must make the total 6450 or more $\Large 6a+3.5c \ge 6450$

4. jim_thompson5910

forming the two inequalities gets you this system $\Large \begin{cases} a+c \le 1200\\6a+3.5c \ge 6450\end{cases}$ and this system will help you determine the optimal amount of tickets to sell to each group

5. anonymous

THANKS MAN I REALLY APPRECIATE!!!