anonymous
  • anonymous
THIS IS REALLY CONFUSING Choose the system of linear inequalities that represent the given scenario. Let a represent the number of adult tickets and let c represent the number of children tickets. There were up to 1,200 tickets available for the spring carnival. Adult tickets cost $6.00 and children’s tickets cost $3.50. How many tickets of each could be sold to make at least $6,450? A;https://media.education2020.com/evresources/2066753_answer_choice_a.png B;https://media.education2020.com/evresources/2066753_answer_choice_b.png Chttps://media.education2020.com/evresources/2066753_answe
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
D;https://media.education2020.com/evresources/2066753_answer_choice_d.png
jim_thompson5910
  • jim_thompson5910
a = # of adult tickets c = # of child tickets a+c represents all of the tickets sold because you can only choose one or the other since "There were up to 1,200 tickets available", this means \[\Large a+c \le 1200\] the key word here is "up to" which means "maximum". The 1200 is the highest we can go in terms of total number of tickets
jim_thompson5910
  • jim_thompson5910
"Adult tickets cost $6.00 and children’s tickets cost $3.50." 'a' adult tickets are sold, so they rake in 6a dollars c child tickets are sold, they rake in 3.5c dollars in total, the combined total is 6a+3.5c dollars we want to "make at least $6,450", which means we must make the total 6450 or more \[\Large 6a+3.5c \ge 6450\]

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jim_thompson5910
  • jim_thompson5910
forming the two inequalities gets you this system \[\Large \begin{cases} a+c \le 1200\\6a+3.5c \ge 6450\end{cases}\] and this system will help you determine the optimal amount of tickets to sell to each group
anonymous
  • anonymous
THANKS MAN I REALLY APPRECIATE!!!

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