anyone good with quartiles??? like with stem and leaf plots, and box and whisker plots??? i will fan and medal anyone who helps!! :)

- anonymous

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- chestercat

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- anonymous

i have two questions...but cant really figure them out...can someone help?? i will fan or medal or do both

- jim_thompson5910

post your question

- anonymous

k, one sec

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## More answers

- anonymous

What is the first quartile (Q1) of the data set?
51, 42, 46, 53, 66, 70, 90, 70
48.5
59.5
61
70

- jim_thompson5910

first off, you'll need to find the median. To do that, you sort the data from smallest to biggest and pick out the middle-most value

- jim_thompson5910

|dw:1433220603820:dw|

- jim_thompson5910

|dw:1433220620697:dw|

- jim_thompson5910

|dw:1433220645867:dw|

- jim_thompson5910

what median do you get?

- anonymous

i got 46

- anonymous

sorry wrong answer lol

- jim_thompson5910

try again

- anonymous

59.5 is my real answer that i got

- jim_thompson5910

59.5 is the median, yes

- anonymous

k whats the next step?

- jim_thompson5910

what we do from here is cut the data set in half based on that median
the first quartile will come from this data set circled
|dw:1433221087759:dw|
I have circled everything smaller than the median

- jim_thompson5910

find the median of that subset, of this list of numbers
42, 46, 51, 53
to get the value of Q1

- jim_thompson5910

|dw:1433221141622:dw|

- anonymous

so 48.5?

- jim_thompson5910

|dw:1433221173116:dw|

- jim_thompson5910

48.5 is Q1, correct

- anonymous

yay!!! can you help with one more...its for Q3

- jim_thompson5910

sure

- anonymous

k thanks! :)

- anonymous

What is the third quartile (Q3) of the data set?
165, 85, 105, 105, 152, 144, 140, 160, 80
105
140
156
160

- jim_thompson5910

you'll follow the same steps, but instead of focusing on the lower half, you do the upper half

- anonymous

k, ill try and find the answer now....

- jim_thompson5910

step 1) sort the data
step 2) find the median
step 3) circle the group of values larger than the median or to the right of it
step 4) in this sub-group, find the median to get Q3

- anonymous

i got 156...is that correct?

- jim_thompson5910

Q3 = 156 is correct

- anonymous

yay!! and thank you so much! you are very kind! :)

- jim_thompson5910

glad to be of help

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