anonymous
  • anonymous
anyone good with quartiles??? like with stem and leaf plots, and box and whisker plots??? i will fan and medal anyone who helps!! :)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i have two questions...but cant really figure them out...can someone help?? i will fan or medal or do both
jim_thompson5910
  • jim_thompson5910
post your question
anonymous
  • anonymous
k, one sec

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anonymous
  • anonymous
What is the first quartile (Q1) of the data set? 51, 42, 46, 53, 66, 70, 90, 70 48.5 59.5 61 70
jim_thompson5910
  • jim_thompson5910
first off, you'll need to find the median. To do that, you sort the data from smallest to biggest and pick out the middle-most value
jim_thompson5910
  • jim_thompson5910
|dw:1433220603820:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1433220620697:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1433220645867:dw|
jim_thompson5910
  • jim_thompson5910
what median do you get?
anonymous
  • anonymous
i got 46
anonymous
  • anonymous
sorry wrong answer lol
jim_thompson5910
  • jim_thompson5910
try again
anonymous
  • anonymous
59.5 is my real answer that i got
jim_thompson5910
  • jim_thompson5910
59.5 is the median, yes
anonymous
  • anonymous
k whats the next step?
jim_thompson5910
  • jim_thompson5910
what we do from here is cut the data set in half based on that median the first quartile will come from this data set circled |dw:1433221087759:dw| I have circled everything smaller than the median
jim_thompson5910
  • jim_thompson5910
find the median of that subset, of this list of numbers 42, 46, 51, 53 to get the value of Q1
jim_thompson5910
  • jim_thompson5910
|dw:1433221141622:dw|
anonymous
  • anonymous
so 48.5?
jim_thompson5910
  • jim_thompson5910
|dw:1433221173116:dw|
jim_thompson5910
  • jim_thompson5910
48.5 is Q1, correct
anonymous
  • anonymous
yay!!! can you help with one more...its for Q3
jim_thompson5910
  • jim_thompson5910
sure
anonymous
  • anonymous
k thanks! :)
anonymous
  • anonymous
What is the third quartile (Q3) of the data set? 165, 85, 105, 105, 152, 144, 140, 160, 80 105 140 156 160
jim_thompson5910
  • jim_thompson5910
you'll follow the same steps, but instead of focusing on the lower half, you do the upper half
anonymous
  • anonymous
k, ill try and find the answer now....
jim_thompson5910
  • jim_thompson5910
step 1) sort the data step 2) find the median step 3) circle the group of values larger than the median or to the right of it step 4) in this sub-group, find the median to get Q3
anonymous
  • anonymous
i got 156...is that correct?
jim_thompson5910
  • jim_thompson5910
Q3 = 156 is correct
anonymous
  • anonymous
yay!! and thank you so much! you are very kind! :)
jim_thompson5910
  • jim_thompson5910
glad to be of help

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