At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

oh I know where I calculated wrong.
in that
c/a and forgot that a was =4 and not 2

would it be
b^2 = 2?

nope that's not right either.

bad at circle and conics
sorry :(

Thanks for looking at it though. Ah well.

axis**

It would have a vertical major axis so (x-h)^2/b^2 + (y-k)^2/a^2 =1
where 2b=8

how do I find the minor axis in there?

eccentricity = sqrt(a^2-b^2)/a

b^2 = a^2(1-e^2)

so from this you can find the minor axis

hmm

focii are on the y-axis so h=0

so
x^2/8 + y^2/16 = 1

is that the answer?

@iambatman save me. lol

Hollllllaaaa

aloo

major axis = 8 ye?

I just need to find an equation :P

yeah

major axis = 2a
so a = 4

vertically?

That sounds good, so what should we do next

You should already realize an error in your work with that information

a should be the bigger one?

You're too good :)

Aw, shucks.

so what numbers do i flip around?

Well lets find b first

To do that we have \[e = \frac{ c }{ a }\] and \[c^2 = a^2 - b^2\]

e = sq7/2
but we're given that a = 4 so do we double that whole thing?

What was that cute game we were playing earlier? I had a name for it

lol substitution?

Yeah that's it ;)

but we're given the e!

So what's stopping you from solving for c :)

no b?

We have a and e!

ooh oh

sq7/2=c/4

:))))

So what will be our c value?

sq14?

\[2\sqrt{7}\]

Looks good, now what's our next step :)

find b!

Right, and how will we do that

so that's just c, not c^2

Yes good observation!

so now
c^2=a^2+b^2

Stop right there for a second!

o.o yes sir.

Lets look at the equation you said, what is that for :)

c

ircle

lol

That's where a lot of people make mistakes, for an ellipse it's \[c^2 = a^2 - b^2\]

Note the negative sign

o.o gasp. that is no bueno.

b^2=a^2-c^2 then

:), now remember as I always say it's a game of substitution

\[b^2 = 16 - (2\sqrt{7})^2\]

\[b^2 = 16-28\]
\[b^2=-12\]

\[b=\sqrt{12}\]

No, the negative is there, something is wrong

..oh hehe

I guess I should be doing the math as well haha

sorry!

ai ai ai I need to go to bed soon. waay to early on a school night =.= and you do too.

No it's alright we just had mistaken the eccentricity we had sqrt(7)/2 when it's 4 :P

oh xD

Don't worry about me :), I'm the dark knight, night is where I work muahah!

right, right, how could I forget!

Alright so lets find b again bleh :)

\[b^2 = a^2-c^2\]

\[a = 4~~~c = \sqrt{7}\]

b = 3

b^2 = 9

Now that looks good

so..the answer I had at the very beginning. Look at the screenshot thing =.=

major axis runs vertically :P

ooh myy goooshh aspidghpaihgpi

fricken hour later hahahah

It's ok, the struggle is more important than the final answer, you will remember how to do it now :)

we're geniuses! :)

for sure though!

Not me, you are a genius! You deserve a fields medal hehe!

noo no bro the answers wrong still
D:

What did you put

Nope.

a = 4, a^2 = 16

...can you write out the whole answer just so i make sure to put it right?

and y runs vertically hence \[\frac{ x^2 }{ 9 }+ \frac{ y^2 }{ 16 } = 1\]

That little green mark though :')

Yes, sorry about that I did not check if you put a^2

it's all good :) so it was indeed my first answer just forgot to ^2 the a

haha cuz we hate the players (not really) but love the game ;)

yes indeed!

*hug hug hug. you are a trooper. haha and with that. I am off to bed.

Take care :)

Night, Batman.