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Ahsome
 one year ago
Absolute Value question
Ahsome
 one year ago
Absolute Value question

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ahsome
 one year ago
Best ResponseYou've already chosen the best response.0Assuming \(x+iy1 = x+iy2i\), express \(y\) in terms of \(x\) Where \(x,y\in\mathbb{R}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433247964097:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0z is a complex number equidistant from (1,0) and (0,2) so it is a straight line perpendicular to the line joining both of them and passing through the mid point you will get the relation between y and x

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0I am confused. What do you mean by \(\mathbf{equidistant }\)?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1let \(z=x+iy\) then the given equation is same as \[z1 = z2i\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1recall that z1 gives you the distance between \(z\) and \(1+0i\) and z2i gives the distance between \(z\) and \(0+2i\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1if you don't like that geometric thingy, you may work it algebraically : \[x+iy1 = x+iy2i\\~\\(x1)+iy=x+i(y2)\\~\\(x+1)^2+y^2 = x^2+(y2)^2\] simplify

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0May I ask, why you squared everything?

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0I get \[y=\dfrac{2x}{4}+\dfrac{3}{4}\]. Is that right?

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0Why did: \[(x−1)+iy=x+i(y−2) \]Become\[ (x+1)^2+y^2=x^2+(y−2)^2\], Instead of\[ (x1)^2+y^2=x^2+(y−2)^2\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Ahh thats just my mistake!

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0The answer I get is \[\huge{y=\dfrac{x}{2}+\dfrac{3}{4}}\]

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0The answer in the book is\[\huge{y=\dfrac{x}{4}+\dfrac{3}{4}}\]

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0What do you think is the issue, @ganeshie8?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1y = x/2 + 3/4 is right

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1your textbook must be having a typo

ahsome
 one year ago
Best ResponseYou've already chosen the best response.0Ahh, ok then. Thanks so much!. Could you help me with another question?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1wil try, pls post as a new q so that it gets bumped in the top and others see
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